Does python enumerate start with 0?

In this tutorial, we will learn about the Python enumerate[] method with the help of examples.

The enumerate[] method adds a counter to an iterable and returns it [the enumerate object].

Example

languages = ['Python', 'Java', 'JavaScript']

enumerate_prime = enumerate[languages]

# convert enumerate object to list
print[list[enumerate_prime]]

# Output: [[0, 'Python'], [1, 'Java'], [2, 'JavaScript']]

Syntax of enumerate[]

The syntax of enumerate[] is:

enumerate[iterable, start=0]

enumerate[] Parameters

enumerate[] method takes two parameters:

• iterable - a sequence, an iterator, or objects that supports iteration
• start [optional] - enumerate[] starts counting from this number. If start is omitted, 0 is taken as start.

enumerate[] Return Value

enumerate[] method adds counter to an iterable and returns it. The returned object is an enumerate object.

You can convert enumerate objects to list and tuple using list[] and tuple[] method respectively.

Example 1: How enumerate[] works in Python?

grocery = ['bread', 'milk', 'butter']
enumerateGrocery = enumerate[grocery]

print[type[enumerateGrocery]]

# converting to list
print[list[enumerateGrocery]]

# changing the default counter
enumerateGrocery = enumerate[grocery, 10]
print[list[enumerateGrocery]]

Output

[[0, 'bread'], [1, 'milk'], [2, 'butter']]
[[10, 'bread'], [11, 'milk'], [12, 'butter']]

Example 2: Looping Over an Enumerate object

grocery = ['bread', 'milk', 'butter']

for item in enumerate[grocery]:
  print[item]

print['\n']

for count, item in enumerate[grocery]:
  print[count, item]

print['\n']
# changing default start value
for count, item in enumerate[grocery, 100]:
  print[count, item]

Output

[0, 'bread']
[1, 'milk']
[2, 'butter']

0 bread
1 milk
2 butter

100 bread
101 milk
102 butter

In Python, you can get the element and index [count] from iterable objects such as list and tuple in for loop with the built-in function enumerate[].

• Built-in Functions - enumerate[] — Python 3.8.5 documentation

This article describes the following contents.

• How to use enumerate[]
  • Normal for loop
  • for loop with enumerate[]
• Start index at 1 with enumerate[]
• Set step with enumerate[]

See the following articles for more information about for loop and how to use enumerate[] and zip[] together.

• for loop in Python [with range, enumerate, zip, etc.]
• Use enumerate[] and zip[] together in Python

How to use enumerate[]

Normal for loop

l = ['Alice', 'Bob', 'Charlie']

for name in l:
    print[name]
# Alice
# Bob
# Charlie

for loop with enumerate[]

By passing an iterable object to enumerate[], you can get index, element.

for i, name in enumerate[l]:
    print[i, name]
# 0 Alice
# 1 Bob
# 2 Charlie

Start index at 1 with enumerate[]

As in the example above, by default, the index of enumerate[] starts at 0.

If you want to start from another number, pass the number to the second argument of enumerate[].

Start at 1:

for i, name in enumerate[l, 1]:
    print[i, name]
# 1 Alice
# 2 Bob
# 3 Charlie

Start at the other number:

for i, name in enumerate[l, 42]:
    print[i, name]
# 42 Alice
# 43 Bob
# 44 Charlie

For example, this is useful when generating sequential number strings starting from 1. It is smarter to pass the starting number to the second argument of enumerate[] than to calculate i + 1.

for i, name in enumerate[l, 1]:
    print['{:03}_{}'.format[i, name]]
# 001_Alice
# 002_Bob
# 003_Charlie

Set step with enumerate[]

There is no argument like step to specify increment to enumerate[], but it can be done as follows.

step = 3
for i, name in enumerate[l]:
    print[i * step, name]
# 0 Alice
# 3 Bob
# 6 Charlie

Does enumerate in Python start at 0?

Does Python enumerate start at 1?

What does enumerate [] do in Python?

What is the output of enumerate?