How do you find the sum of odd numbers in python?

Python program to get input n and calculate the sum of odd numbers till n

Sample Input 1:

5

Sample Output 1:

9[1+3+5]

Program or Solution

				
			
					
n=int[input["Enter n value:"]]
sum=0
for i in range[1,n+1,2]:
    sum+=i
print[sum]
    

			
				
			

Program Explanation

For Statement is used to execute the sequence of instruction repeatedly.

Range[] method gives list of elements, here range[] method gives list which has 1,3,5... to n or n-1. for statement executes the instructions iteratively and for takes the elements one by one as value of i in sequential manner.

so it adds odd numbers.

The following article shows how given an integer list, we can produce the sum of all its odd and even digits.

Input : test_list = [345, 893, 1948, 34, 2346] 
Output : 
Odd digit sum : 36 
Even digit sum : 40 
Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.
Input : test_list = [345, 893] 
Output : 
Odd digit sum : 20 
Even digit sum : 12 
Explanation : 4 + 8 = 12, even summation. 

Method 1 : Using loop, str[] and int[]

In this, we first convert each element to string and then iterate for each of its element, and add to respective summation by conversion to integer.

Python3

test_list = [345, 893, 1948, 34, 2346]

print["The original list is : " + str[test_list]]

odd_sum = 0

even_sum = 0

for sub in test_list:

    for ele in str[sub]:

        if int[ele] % 2 == 0:

            even_sum += int[ele]

        else:

            odd_sum += int[ele]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

The original list is : [345, 893, 1948, 34, 2346]
Odd digit sum : 36
Even digit sum : 40

Method 2: Using loop and sum[]

In this, we perform task of getting summation using sum[], and loop is used to perform the task of iterating through each element.

Python3

test_list = [345, 893, 1948, 34, 2346]

print["The original list is : " + str[test_list]]

odd_sum = 0

even_sum = 0

for sub in test_list:

    odd_sum += sum[[int[ele] for ele in str[sub] if int[ele] % 2 == 1]]

    even_sum += sum[[int[ele] for ele in str[sub] if int[ele] % 2 == 0]]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

The original list is : [345, 893, 1948, 34, 2346]
Odd digit sum : 36
Even digit sum : 40

Method 3: Using list comprehension 

Python3

test_list = [345, 893, 1948, 34, 2346]

odd_sum = 0

even_sum = 0

odd_sum += sum[[int[ele]

                for sub in test_list for ele in str[sub] if int[ele] % 2 == 1]]

even_sum += sum[[int[ele]

                 for sub in test_list for ele in str[sub] if int[ele] % 2 == 0]]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

Odd digit sum : 36
Even digit sum : 40

Method 4: Using the enumerate function

Python3

test_list = [345, 893, 1948, 34, 2346]

odd_sum = 0

even_sum = 0

odd_sum += sum[[int[ele] for i, sub in enumerate[test_list]

                for ele in str[sub] if int[ele] % 2 == 1]]

even_sum += sum[[int[ele] for i, sub in enumerate[test_list]

                 for ele in str[sub] if int[ele] % 2 == 0]]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

Odd digit sum : 36
Even digit sum : 40


How do you find the sum of odd numbers?

The total of any set of sequential odd numbers beginning with 1 is always equal to the square of the number of digits, added together. If 1,3,5,7,9,11,…, [2n-1] are the odd numbers, then; Sum of first odd number = 1. Sum of first two odd numbers = 1 + 3 = 4 [4 = 2 x 2].

How do you find odd numbers in python?

Also, if…else statements will be used. The required code is provided below. num = int [input [“Enter any number to test whether it is odd or even: “] if [num % 2] == 0: print [“The number is even”] else: print [“The provided number is odd”] Output: Enter any number to test whether it is odd or even: 887 887 is odd.

How do you find the sum of a number in python?

See this example:.
num = int[input["Enter a number: "]].
if num < 0:.
print["Enter a positive number"].
sum = 0..
# use while loop to iterate un till zero..
while[num > 0]:.
sum += num..

How do you find the sum of even numbers in a list python?

"] exit[] sum = 0 count = 0 for i in range[tot]: if nums[i]%2 == 0: sum = sum + nums[i] count = count+1 if count==0: print["\nEven number is not found in this list! "] else: print["\nSum of Even Numbers =", sum] except ValueError: print["\nInvalid Size Input!

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