Hướng dẫn dùng time diff trong PHP

How to calculate minute difference between two date-times in PHP?

S.L. Barth

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asked Dec 13, 2008 at 13:05

Tom SmykowskiTom Smykowski

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The answers above are for older versions of PHP. Use the DateTime class to do any date calculations now that PHP 5.3 is the norm. Eg.

$start_date = new DateTime('2007-09-01 04:10:58');
$since_start = $start_date->diff(new DateTime('2012-09-11 10:25:00'));
echo $since_start->days.' days total
';
echo $since_start->y.' years
';
echo $since_start->m.' months
';
echo $since_start->d.' days
';
echo $since_start->h.' hours
';
echo $since_start->i.' minutes
';
echo $since_start->s.' seconds
';

$since_start is a DateInterval object. Note that the days property is available (because we used the diff method of the DateTime class to generate the DateInterval object).

The above code will output:

1837 days total
5 years
0 months
10 days
6 hours
14 minutes
2 seconds

To get the total number of minutes:

$minutes = $since_start->days * 24 * 60;
$minutes += $since_start->h * 60;
$minutes += $since_start->i;
echo $minutes.' minutes';

This will output:

2645654 minutes

Which is the actual number of minutes that has passed between the two dates. The DateTime class will take daylight saving (depending on timezone) into account where the "old way" won't. Read the manual about Date and Time http://www.php.net/manual/en/book.datetime.php

answered Sep 12, 2012 at 7:11

17

Here is the answer:

$to_time = strtotime("2008-12-13 10:42:00");
$from_time = strtotime("2008-12-13 10:21:00");
echo round(abs($to_time - $from_time) / 60,2). " minute";

answered Dec 13, 2008 at 13:36

user38526user38526

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4

Subtract the past most one from the future most one and divide by 60.

Times are done in Unix format so they're just a big number showing the number of seconds from January 1, 1970, 00:00:00 GMT

Noman

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answered Dec 13, 2008 at 13:23

OliOli

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3

answered Dec 13, 2008 at 15:49

TomTom

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3

Output:

75

answered Sep 12, 2019 at 14:10

0

It worked on my programs, i'am using date_diff, you can check date_diff manual on here.

$start = date_create('2015-01-26 12:01:00');
$end = date_create('2015-01-26 13:15:00');
$diff=date_diff($end,$start);
print_r($diff);

You get results what do you want.

answered Jul 9, 2015 at 15:43

yussanyussan

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2

another way with timezone.

$start_date = new DateTime("2013-12-24 06:00:00",new DateTimeZone('Pacific/Nauru'));
$end_date = new DateTime("2013-12-24 06:45:00", new DateTimeZone('Pacific/Nauru'));
$interval = $start_date->diff($end_date);
$hours   = $interval->format('%h'); 
$minutes = $interval->format('%i');
echo  'Diff. in minutes is: '.($hours * 60 + $minutes);

answered Dec 24, 2013 at 13:16

MuhammadMuhammad

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1

I wrote this function for one my blog site(difference between a past date and server's date). It will give you an output like this

"49 seconds ago", "20 minutes ago", "21 hours ago" and so on

I have used a function that would get me the difference between the date passed and the server's date.

format('%s Seconds %i Minutes %h Hours %d days %m Months %y Year    Ago')."
";
    $min=$interval->format('%i');
    $sec=$interval->format('%s');
    $hour=$interval->format('%h');
    $mon=$interval->format('%m');
    $day=$interval->format('%d');
    $year=$interval->format('%y');
    if($interval->format('%i%h%d%m%y')=="00000") {
        //echo $interval->format('%i%h%d%m%y')."
";
        return $sec." Seconds";
    } else if($interval->format('%h%d%m%y')=="0000"){
        return $min." Minutes";
    } else if($interval->format('%d%m%y')=="000"){
        return $hour." Hours";
    } else if($interval->format('%m%y')=="00"){
        return $day." Days";
    } else if($interval->format('%y')=="0"){
        return $mon." Months";
    } else{
        return $year." Years";
    }    
}
?>

Save it as a file suppose "date.php". Call the function from another page like this

 ";
 echo dateDiff($mydate);
?>

Of course you can modify the function to pass two values.

RiggsFolly

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answered Jun 7, 2014 at 19:21

0

DateTime::diff is cool, but awkward for this sort of calculations that require a single unit result. Manually subtracting the timestamps works better:

$date1 = new DateTime('2020-09-01 01:00:00');
$date2 = new DateTime('2021-09-01 14:00:00');
$diff_mins = abs($date1->getTimestamp() - $date2->getTimestamp()) / 60;

answered May 25, 2021 at 15:26

Şafak GezerŞafak Gezer

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I think this will help you

function calculate_time_span($date){
    $seconds  = strtotime(date('Y-m-d H:i:s')) - strtotime($date);

        $months = floor($seconds / (3600*24*30));
        $day = floor($seconds / (3600*24));
        $hours = floor($seconds / 3600);
        $mins = floor(($seconds - ($hours*3600)) / 60);
        $secs = floor($seconds % 60);

        if($seconds < 60)
            $time = $secs." seconds ago";
        else if($seconds < 60*60 )
            $time = $mins." min ago";
        else if($seconds < 24*60*60)
            $time = $hours." hours ago";
        else if($seconds < 24*60*60)
            $time = $day." day ago";
        else
            $time = $months." month ago";

        return $time;
}

answered Oct 31, 2014 at 5:26

2

This is how I displayed "xx times ago" in php > 5.2 .. here is more info on DateTime object

//Usage:
$pubDate = $row['rssfeed']['pubDates']; // e.g. this could be like 'Sun, 10 Nov 2013 14:26:00 GMT'
$diff = ago($pubDate);    // output: 23 hrs ago

// Return the value of time different in "xx times ago" format
function ago($timestamp)
{

    $today = new DateTime(date('y-m-d h:i:s')); // [2]
    //$thatDay = new DateTime('Sun, 10 Nov 2013 14:26:00 GMT');
    $thatDay = new DateTime($timestamp);
    $dt = $today->diff($thatDay);

    if ($dt->y > 0){
        $number = $dt->y;
        $unit = "year";
    } else if ($dt->m > 0) {
        $number = $dt->m;
        $unit = "month";
    } else if ($dt->d > 0) {
        $number = $dt->d;
        $unit = "day";
    } else if ($dt->h > 0) {
        $number = $dt->h;
        $unit = "hour";
    } else if ($dt->i > 0) {
        $number = $dt->i;
        $unit = "minute";
    } else if ($dt->s > 0) {
        $number = $dt->s;
        $unit = "second";
    }
    
    $unit .= $number  > 1 ? "s" : "";
 
    $ret = $number." ".$unit." "."ago";
    return $ret;
}

RiggsFolly

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answered Mar 27, 2014 at 4:11

hriziyahriziya

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function date_getFullTimeDifference( $start, $end )
{
$uts['start']      =    strtotime( $start );
        $uts['end']        =    strtotime( $end );
        if( $uts['start']!==-1 && $uts['end']!==-1 )
        {
            if( $uts['end'] >= $uts['start'] )
            {
                $diff    =    $uts['end'] - $uts['start'];
                if( $years=intval((floor($diff/31104000))) )
                    $diff = $diff % 31104000;
                if( $months=intval((floor($diff/2592000))) )
                    $diff = $diff % 2592000;
                if( $days=intval((floor($diff/86400))) )
                    $diff = $diff % 86400;
                if( $hours=intval((floor($diff/3600))) )
                    $diff = $diff % 3600;
                if( $minutes=intval((floor($diff/60))) )
                    $diff = $diff % 60;
                $diff    =    intval( $diff );
                return( array('years'=>$years,'months'=>$months,'days'=>$days, 'hours'=>$hours, 'minutes'=>$minutes, 'seconds'=>$diff) );
            }
            else
            {
                echo "Ending date/time is earlier than the start date/time";
            }
        }
        else
        {
            echo "Invalid date/time data detected";
        }
}

answered Jan 28, 2015 at 7:05

VeerendraVeerendra

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A more universal version that returns result in days, hours, minutes or seconds including fractions/decimals:

function DateDiffInterval($sDate1, $sDate2, $sUnit='H') {
//subtract $sDate2-$sDate1 and return the difference in $sUnit (Days,Hours,Minutes,Seconds)
    $nInterval = strtotime($sDate2) - strtotime($sDate1);
    if ($sUnit=='D') { // days
        $nInterval = $nInterval/60/60/24;
    } else if ($sUnit=='H') { // hours
        $nInterval = $nInterval/60/60;
    } else if ($sUnit=='M') { // minutes
        $nInterval = $nInterval/60;
    } else if ($sUnit=='S') { // seconds
    }
    return $nInterval;
} //DateDiffInterval

answered Jun 1, 2017 at 22:19

besimplebesimple

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1

Subtract the times and divide by 60.

Here is an example which calculate elapsed time from 2019/02/01 10:23:45 in minutes:

$diff_time=(strtotime(date("Y/m/d H:i:s"))-strtotime("2019/02/01 10:23:45"))/60;

answered Oct 30, 2019 at 14:54

My solution to find the difference between two dates is here. With this function you can find differences like seconds, minutes, hours, days, years and months.

function alihan_diff_dates($date = null, $diff = "minutes") {
 $start_date = new DateTime($date);
 $since_start = $start_date->diff(new DateTime( date('Y-m-d H:i:s') )); // date now
 print_r($since_start);
 switch ($diff) {
    case 'seconds':
        return $since_start->s;
        break;
    case 'minutes':
        return $since_start->i;
        break;
    case 'hours':
        return $since_start->h;
        break;
    case 'days':
        return $since_start->d;
        break;      
    default:
        # code...
        break;
 }
}

You can develop this function. I tested and works for me. DateInterval object output is here:

/*
DateInterval Object ( [y] => 0 [m] => 0 [d] => 0 [h] => 0 [i] => 5 [s] => 13 [f] => 0 [weekday] => 0 [weekday_behavior] => 0 [first_last_day_of] => 0 [invert] => 0 [days] => 0 [special_type] => 0 [special_amount] => 0 [have_weekday_relative] => 0 [have_special_relative] => 0 ) 
*/

Function Usage:

$date = the past date, $diff = type eg: "minutes", "days", "seconds"

$diff_mins = alihan_diff_dates("2019-03-24 13:24:19", "minutes");

Good Luck.

answered Mar 24, 2019 at 2:52

Ali HanAli Han

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$date1=date_create("2020-03-15");
$date2=date_create("2020-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");

For detailed format specifiers, visit the link.

answered Nov 1, 2020 at 11:42

snrsnr

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Another simple way to calculate the difference in minutes. Please note this is a sample for calculating within a 1-year range. for more details click here

$origin = new DateTime('2021-02-10 09:46:32');
$target = new DateTime('2021-02-11 09:46:32');
$interval = $origin->diff($target);
echo (($interval->format('%d')*24) + $interval->format('%h'))*60; //1440 (difference in minutes)

answered Feb 13, 2021 at 20:20

This will help....

function get_time($date,$nosuffix=''){
    $datetime = new DateTime($date);
    $interval = date_create('now')->diff( $datetime );
    if(empty($nosuffix))$suffix = ( $interval->invert ? ' ago' : '' );
    else $suffix='';
    //return $interval->y;
    if($interval->y >=1)        {$count = date(VDATE, strtotime($date)); $text = '';}
    elseif($interval->m >=1)    {$count = date('M d', strtotime($date)); $text = '';}
    elseif($interval->d >=1)    {$count = $interval->d; $text = 'day';} 
    elseif($interval->h >=1)    {$count = $interval->h; $text = 'hour';}
    elseif($interval->i >=1)    {$count = $interval->i; $text = 'minute';}
    elseif($interval->s ==0)    {$count = 'Just Now'; $text = '';}
    else                        {$count = $interval->s; $text = 'second';}
    if(empty($text)) return ' '.$count;
    return ' '.$count.(($count ==1)?(" $text"):(" ${text}s")).' '.$suffix;     
}

answered Jan 16, 2018 at 4:57

GYaNGYaN

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1

I found so many solution but I never got correct solution. But i have created some code to find minutes please check it.

= $mins1) {
        $mins = $mins2 - $mins1;
    }
    else {
      $mins = ($mins2 + 60) - $mins1;
      $hours--;
    }
    if($mins < 9)
    {
      $mins = str_pad($mins, 2, '0', STR_PAD_LEFT);
    }
    if($hours < 9)
    {
      $hours =str_pad($hours, 2, '0', STR_PAD_LEFT);
    }
echo $hours.':'.$mins;
?>

It gives output in hours and minutes for example 01 hour 02 minutes like 01:02

answered Jun 5, 2019 at 9:45

Here is a simple one-liner:

$start = new DateTime('yesterday');
$end = new DateTime('now');
$diffInMinutes = iterator_count(new \DatePeriod($start, new \DateInterval('PT1M'), $end));

answered Nov 30, 2021 at 17:11

nimrodnimrod

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try this

$now = \Carbon\Carbon::now()->toDateString(); // get current time 
             $a = strtotime("2012-09-21 12:12:22"); 
             $b = strtotime($now);
             $minutes = ceil(($a - $b) / 3600); it will get ceiling value 

answered May 8, 2021 at 8:43

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