A number is even if it is perfectly divisible by 2. When the number is divided by 2, we use the remainder operator % to compute the remainder. If the remainder is not zero, the number is odd.
Source Code
# Python program to check if the input number is odd or even.
# A number is even if division by 2 gives a remainder of 0.
# If the remainder is 1, it is an odd number.
num = int[input["Enter a number: "]]
if [num % 2] == 0:
print["{0} is Even".format[num]]
else:
print["{0} is Odd".format[num]]Output 1
Enter a number: 43 43 is Odd
Output 2
Enter a number: 18 18 is Even
In this program, we ask the user for the input and check if the number is odd or even. Please note that { } is a replacement field for num.
A number is even if it is perfectly divisible by 2. When the number is divided by 2, we use the remainder operator % to compute the remainder. If the remainder is not zero, the number is odd.
Nội dung chính
- Source Code
- Python Program to Check if a Number is Odd or Even
- Help Others, Please Share
- Python Basic: Exercise-21 with Solution
- Visualize Python code execution:
- Python: Tips of the Day
- Method: Using the enumerate function
Source Code
# Python program to check if the input number is odd or even.
# A number is even if division by 2 gives a remainder of 0.
# If the remainder is 1, it is an odd number.
num = int[input["Enter a number: "]]
if [num % 2] == 0:
print["{0} is Even".format[num]]
else:
print["{0} is Odd".format[num]]Output 1
Enter a number: 43 43 is Odd
Output 2
Enter a number: 18 18 is Even
In this program, we ask the user for the input and check if the number is odd or even. Please note that { } is a replacement field for num.
Python Program to Check if a Number is Odd or Even
Odd and Even numbers:
If you divide a number by 2 and it gives a remainder of 0 then it is known as even number, otherwise an odd number.
Even number examples: 2, 4, 6, 8, 10, etc.
Odd number examples:1, 3, 5, 7, 9 etc.
See this example:
Output:
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Python Basic: Exercise-21 with Solution
Write a Python program to find whether a given number [accept from the user] is even or odd, print out an appropriate message to the user.
Pictorial Presentation of Even Numbers:
Pictorial Presentation of Odd Numbers:
Sample Solution:-
Python Code:
num = int[input["Enter a number: "]]
mod = num % 2
if mod > 0:
print["This is an odd number."]
else:
print["This is an even number."]
Sample Output:
Enter a number: 5 This is an odd number.
Even Numbers between 1 to 100:
Odd Numbers between 1 to 100:
Flowchart:
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Previous: Write a Python program to get a string which is n [non-negative integer] copies of a given string.
Next: Write a Python program to count the number 4 in a given list.
Python: Tips of the Day
Convert a dict to XML:
from xml.etree.ElementTree import Elementdef dict_to_xml[tag, d]:
'''
Turn a simple dict of key/value pairs into XML
'''
elem = Element[tag]
for key, val in d.items[]:
child = Element[key]
child.text = str[val]
elem.append[child]
return elem
Given a list of numbers, write a Python program to count Even and Odd numbers in a List. Example:
Input: list1 = [2, 7, 5, 64, 14] Output: Even = 3, odd = 2 Input: list2 = [12, 14, 95, 3] Output: Even = 2, odd = 2
Example 1: count Even and Odd numbers from given list using for loop Iterate each element in the list using for loop and check if num % 2 == 0, the condition to check even numbers. If the condition satisfies, then increase even count else increase odd count.
Python3
list1 = [10, 21, 4, 45, 66, 93, 1]
even_count, odd_count = 0, 0
for num in list1:
if
num % 2 == 0:
even_count += 1
else:
odd_count += 1
print["Even numbers in the list: ", even_count]
print["Odd numbers in the list: ", odd_count]
Output:
Even numbers in the list: 3 Odd numbers in the list: 4
Example 2: Using while loop
Python3
list1 =
[10, 21, 4, 45, 66, 93, 11]
even_count, odd_count = 0, 0
num = 0
while[num < len[list1]]:
if list1[num] % 2 == 0:
even_count += 1
else:
odd_count += 1
num += 1
print["Even numbers in the list: ", even_count]
print["Odd numbers in the list: ", odd_count]
Output:
Even numbers in the list: 3 Odd numbers in the list: 4
Example 3 : Using Python Lambda Expressions
Python3
list1 = [10, 21, 4, 45, 66, 93, 11]
odd_count =
len[list[filter[lambda x: [x%2 != 0] , list1]]]
even_count = len[list[filter[lambda x: [x%2 == 0] , list1]]]
print["Even numbers in the list: ", even_count]
print["Odd numbers in the list: ", odd_count]
Output:
Even numbers in the list: 3 Odd numbers in the list: 4
Example 4 : Using List Comprehension
Python3
list1 =
[10, 21, 4, 45, 66, 93, 11]
only_odd = [num for num in list1 if num % 2 == 1]
odd_count = len[only_odd]
print["Even numbers in the list: ", len[list1] - odd_count]
print["Odd numbers in the list: ", odd_count]
Output:
Even numbers in the list: 3 Odd numbers in the list: 4
Example 5: Using Recursion
Python3
even_count=0
i=0
odd_count=0
def evenoddcount[lst]:
global even_count
global odd_count
global i
if lst[i]%2==0:
even_count+=1
else:
odd_count+=1
if i in
range[len[lst]-1]:
i+=1
evenoddcount[lst]
else:
print["Even numbers in the list: ", even_count]
print["Odd numbers in the list: ", odd_count]
list1 = [10, 21, 4, 45, 66, 93, 1]
evenoddcount[list1]
Output
Even numbers in the list: 3 Odd numbers in the list: 4
Example 6: Using Bitwise XOR operator
The idea is to check whether the last bit of the number is set or not. If the last bit is set then the number is odd, otherwise even. As we know bitwise XOR Operation of the Number by 1 increments the value of the number by 1 if the number is even otherwise it decrements the value of the number by 1 if the value is odd.
CHECK IF NUMBER IS EVEN OR ODD USING XOR OPERATOR
Python3
list1 = [10, 21, 4, 45, 66, 93, 1]
even_count, odd_count = 0, 0
for num in list1:
if
num ^ 1 == num + 1:
even_count += 1
else:
odd_count += 1
print["Even numbers in the list: ", even_count]
print["Odd numbers in the list: ", odd_count]
Output
Even numbers in the list: 3 Odd numbers in the list: 4
Example 7: Using Bitwise AND operator
The idea is to check whether the last bit of the number is set or not. If the last bit is set then the number
is odd, otherwise even.
As we know bitwise AND Operation of the Number by 1 will be 1, If it is odd because the last bit will be already set. Otherwise, it will give 0 as output.
Python3
list1 = [10, 21, 4, 45, 66, 93, 1]
even_count, odd_count = 0, 0
for num in list1:
if not num & 1:
even_count +=
1
else:
odd_count += 1
print["Even numbers in the list: ", even_count]
print["Odd numbers in the list: ", odd_count]
Output
Even numbers in the list: 3 Odd numbers in the list: 4
Example 8: Using Bitwise OR operator
The idea is to check whether the last bit of the number is set or not. If the last bit is set then the number is odd, otherwise even. As we know bitwise OR Operation of the Number by 1 increments the value of the number by 1 if the number is even otherwise it will remain unchanged. So, if after OR operation of number with 1 gives a result which is greater than the number then it is even and we will return true otherwise it is odd and we will return false.
Python3
list1 = [10, 21, 4, 45, 66, 93, 1]
even_count, odd_count = 0, 0
for num in list1:
if
num | 1 > num:
even_count += 1
else:
odd_count += 1
print["Even numbers in the list: ", even_count]
print["Odd numbers in the list: ", odd_count]
Output
Even numbers in the list: 3 Odd numbers in the list: 4
Method: Using the enumerate function
Python3
lst =
[12, 14, 95, 3];c=0;c1=0
for i,a in enumerate[lst]:
if a%2==0:
c+=1
else:
c1+=1
print["even number count",c,"odd number count",c1]
Output
even number count 2 odd number count 2
Auxiliary Space: O[1]