Indivisible Numbers
This Program name is Indivisible Numbers. Write a Python program to Indivisible Numbers
The below link contains Indivisible Numbers question, explanation and test cases
//drive.google.com/file/d/1f7eIquKcLG9PWczki8tG3PWLRrqX3HR1/view?usp=sharing
We need exact output when the code was run
def isDivisible[K]:
counter=0
for n in range[2,11]:
if K%n==0:
counter+=1
return [counter>0]
N=int[input[]]
indivisibleNumber=0
for K in range[1,N+1]:
if not isDivisible[K]:
indivisibleNumber +=1
print[indivisibleNumber]Learn more about our help with Assignments: Python
Answer to Question #220523 in Python for raj
Indivisible Numbers
You are given a positive integer
The first line of input is an integer
The output should be an integer representing the number of positive integers satisfying the above condition.
In the given example,
11 is not divisible by any number from 2 to 10. It is divisible by only 1, 11.So, the output should be
2.
N=int[input["Enter a positive integer: "]]
find=0
for K in range [1,N+1]:
if [N%K==0]:
find +=1
print[find]Learn more about our help with Assignments: Python
Harry August 22, 2022
We will use a list to save numbers and will find the average of given numbers in the list. We know that to find the average of numbers, we simply divide the sum of all numbers by the count of all numbers. For example, to find the average of 2, 3, 4, and 5, we will simply add them[2+3+4+5 = 14] and simply divide them with 4[14÷4 = 3.5]. Now let’s convert the whole process to find the average of the given numbers with Python Code.
1. Python Code to find the average of given numbers using built-in methods
numbers = [1, 2, 3, 4]
total = sum[numbers]
average = total/len[numbers]
print[average]Output:
2.5
2. Python Code to find the average of given numbers using for loop
numbers = [1, 2, 3, 4]
total = 0
count=0
for i in numbers:
total = total + i
count = count + 1
average = total/count
print[average]Output:
2.5Also Read:
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Author: Harry
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