Python program for sum of n numbers using while loop

In the program below, we've used an if...else statement in combination with a while loop to calculate the sum of natural numbers up to num.

Source Code

# Sum of natural numbers up to num

num = 16

if num < 0:
   print["Enter a positive number"]
else:
   sum = 0
   # use while loop to iterate until zero
   while[num > 0]:
       sum += num
       num -= 1
   print["The sum is", sum]

Output

The sum is 136

Note: To test the program for a different number, change the value of num.

Initially, the sum is initialized to 0. And, the number is stored in variable num.

Then, we used the while loop to iterate until num becomes zero. In each iteration of the loop, we have added the num to sum and the value of num is decreased by 1.

We could have solved the above problem without using a loop by using the following formula.

n*[n+1]/2

For example, if n = 16, the sum would be [16*17]/2 = 136.

Your turn: Modify the above program to find the sum of natural numbers using the formula below.

The question was tp :write a program to find the sum of n natural numbers using while loop in python.

n = int[input["Enter a number: "]]
i = 1
while i 0]:
    totalSum += number
    number -= 1
    print ["The sum is" , totalSum]

answered Jul 28 at 21:45

num = int[input['Enter the number : ']]
sum = 0
while 0 0]:.