What is the least number which when divided by 36 and 48 leave 8 as remainder in each case?
|
Solution: Show
We will be using the concept of LCM(Least Common Multiple) to solve this. To determine the least number which when divided by 6, 15, and 18 leave the remainder 5 in each case,we need to find the LCM of the three given numbers. Since, the LCM obtained will be the smallest common multiple of all the three numbers 6, 15, and 18, after getting LCM we need to add 5 to it so as to get 5 as a remainder. Let's find the LCM of 6, 5 and 18 as shown below.  Therefore, LCM of 6, 15 and 18 = 2 × 3 × 3 × 5 = 90. Thus we can see that, 90 is the least number exactly divisible by 6, 15, and 18. To get a remainder 5, we need to add 5 to the LCM. ⇒ 90 + 5 = 95. Thus, when 95 is divided by 6, 15, and 18 we get a remainder of 5 in each case. Hence, the required number for the given problem is 95. You can also use the LCM Calculator to solve this. NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.7 Question 8 Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each caseSummary: The least number which when divided by 6, 15, and 18 leaving a remainder of 5 in each case will be 95. ☛ Related Questions:
Course NCERT Class 12Class 11Class 10Class 9Class 8Class 7Class 6 IIT JEE Exam JEE MAINSJEE ADVANCEDX BOARDSXII BOARDS NEET Neet Previous Year (Year Wise)Physics Previous YearChemistry Previous YearBiology Previous YearNeet All Sample PapersSample Papers BiologySample Papers PhysicsSample Papers Chemistry Download PDF's Class 12Class 11Class 10Class 9Class 8Class 7Class 6 Exam CornerOnline ClassQuizAsk Doubt on WhatsappSearch DoubtnutEnglish DictionaryToppers TalkBlogJEE Crash CourseAbout UsCareerDownloadGet AppTechnothlon-2019 Logout Login Register now for special offers +91 Home > English > Class 7 > Maths > Chapter > Number System > Find the least number which wh... Updated On: 27-06-2022 UPLOAD PHOTO AND GET THE ANSWER NOW! Text Solution 124144164224 Answer : B Answer Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. Related Videos646301785 0 4.5 K 2:24 Find the least number which when divided by 12, 24, 36 and 40 leaves a remainder 1, but when divided by 7 leaves no remainder. 646467386 0 9.6 K 1:46 वह लघुत्तम संख्या ज्ञात कीजिए जिसे 15, 20, 36 और 48 से भाग दिये जाने पर हर बार 3 शेष रहे ? 648175058 0 5.3 K वह लघुत्तम संख्या ज्ञात कीजिए जिसे 24 और 36 से विभाजित करने पर शेषफल क्रमशः 14 और 26 होंगें 571223276 0 4.2 K 3:24 Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case. 648119171 200 8.1 K 1:56 सबसे छोटी संख्या जिसे 36, 48 और 112 से भाग देने पर शेष शून्य बचे - 648549627 300 4.4 K 1:56 सबसे छोटी संख्या जिसे 36, 48 और 112 से भाग देने पर शेष शून्य बचे । Show More Comments Add a public comment... Follow Us: Popular Chapters by Class: Class 6 AlgebraBasic Geometrical IdeasData HandlingDecimalsFractions Class 7 Algebraic ExpressionsComparing QuantitiesCongruence of TrianglesData HandlingExponents and Powers Class 8 Algebraic Expressions and IdentitiesComparing QuantitiesCubes and Cube RootsData HandlingDirect and Inverse Proportions Class 9 Areas of Parallelograms and TrianglesCirclesCoordinate GeometryHerons FormulaIntroduction to Euclids Geometry Class 10 Areas Related to CirclesArithmetic ProgressionsCirclesCoordinate GeometryIntroduction to Trigonometry Class 11 Binomial TheoremComplex Numbers and Quadratic EquationsConic SectionsIntroduction to Three Dimensional GeometryLimits and Derivatives Class 12 Application of DerivativesApplication of IntegralsContinuity and DifferentiabilityDeterminantsDifferential Equations Privacy PolicyTerms And Conditions Disclosure PolicyContact Us What is the least number which when divided by 36 and 48 leaves 8 as remainder?Answer. Answer: if we divide 440 by 48 and 36 leaves 8 as remainder.
What is the least number which when divided by 36 48 and 64 it leaves a remainder of 25 37 and 53 respectively?10 Find the least number which when divided by 36, 48 and 64 leaves the remainders 25, 37 and 53, respectively. Sol. Since (36 – 25) – (48 – 37) = (64 – 53) = 11, therefore the required smallest number (LCM of 36, 48 and 64) –11 = 576 – 11 = 565.
What could be the least number which when we divide by 40 48 and 45 leaves a remainder of 4 in every case?Answer. = 720. Add remainder to the LCM.
What is the least number which on dividing 24 36 48 and 72 leaves remainder 5?Answer = 144 + 8 = 152.
|
