How do i check if a string contains multiple substrings in python?

If you want exact matches of words then consider word tokenizing the target string. I use the recommended word_tokenize from nltk:

from nltk.tokenize import word_tokenize

Here is the tokenized string from the accepted answer:

a_string = "A string is more than its parts!"
tokens = word_tokenize[a_string]
tokens
Out[46]: ['A', 'string', 'is', 'more', 'than', 'its', 'parts', '!']

The accepted answer gets modified as follows:

matches_1 = ["more", "wholesome", "milk"]
[x in tokens for x in matches_1]
Out[42]: [True, False, False]

As in the accepted answer, the word "more" is still matched. If "mo" becomes a match string, however, the accepted answer still finds a match. That is a behavior I did not want.

matches_2 = ["mo", "wholesome", "milk"]
[x in a_string for x in matches_1]
Out[43]: [True, False, False]

Using word tokenization, "mo" is no longer matched:

[x in tokens for x in matches_2]
Out[44]: [False, False, False]

That is the additional behavior that I wanted. This answer also responds to the duplicate question here.

substrings = ['python', 'python3', 'programming']
string = 'Learn programming at pencilprogrammer.com'

result_list = []
for x in substrings:
    # append True/False for substring x
    result_list.append[x in string]
 
#call any[] with boolean results list
print[any[result_list]]

substrings = ['mY', 'naME', 'is', 'KuMAR']
string = 'Author name: Adarsh Kumar'

result_list = []
for x in substrings:
    # append True/False for substring x
    result_list.append[x.lower[] in string.lower[]]
 
#call any[] with boolean results list
print[any[result_list]]

import re

string = 'Python is good for Machine Learning and Data-Science'

"""
pass substrings separated by | as 1st argument
and main string value as 2nd argument.
Additionally, we can pass re.IGNORECASE paramter as
3rd argument to make matching case-insensitive.
"""
match_list = re.findall[r'python|machine|good', string, re.IGNORECASE]

print[any[match_list]]

Python any[] Function

Python any[] function accepts iterable [list, tuple, dictionary etc.] as an argument and return true if any of the element in iterable is true , else it returns false . If the iterable object is empty, the any[] function will return False.

any Vs all

1. any will return True when at least one of the elements is Truthy.
2. all will return True only when all the elements are Truthy.

Check if multiple strings exist in another string

In this case, we can use Python "any[]" .

Here the script return "Found a match", because at least one word exists in the list.

example 2:

output

How to check if string contains substring from list

If your list is too long, it is better to use Python Regular Expression .

Above example return "Found a match" because "one" is exist in the list.

Check If a String Contains Multiple Keywords

You can also find a solution for this by using iteration .

Above script return "Found a match" because "one" is exist in the myList.

All matches including duplicates in a string

If you want to get all the matches including duplicates from the list:

First word match in a string from list

If you want the first match with False as a default:

Above example return "one" because the word "one" is the starting word and exists in the myList also.

How to extract the first and final words from a string?

Similarly to check if all the strings from the list are found, use "all" instead of "any" .

Above example return False because "six" is not in the string.

How do you check if a string contains a list of substrings Python?

How do I check if a string contains more than one character in Python?

How do you check if a list contains multiple values in Python?

How do you check for multiple strings in a string?