The correct solution would use an or.
string = input["Enter a string: "]
if all[x.isalpha[] or x.isspace[] for x in string]:
print["Only alphabetical letters and spaces: yes"]
else:
print["Only alphabetical letters and spaces: no"]
Although you have a string, you are iterating over the letters of that string, so you have one letter at a time. So, a char alone cannot be an alphabetical character AND a space at the time, but it will just need to be one of the two to satisfy your constraint.
EDIT: I saw your comment in the other answer. alphabet = string.isalpha[] return True, if and only if all characters in a string are
alphabetical letters. This is not what you want, because you stated that you want your code to print yes when execute with the string please, which has a space. You need to check each letter on its own, not the whole string.
Just to convince you that the code is indeed correct [well, ok, you need to execute it yourself to be convinced, but anyway]:
>>> string = "please "
>>> if all[x.isalpha[] or x.isspace[] for x in string]:
print["Only alphabetical letters and spaces: yes"]
else:
print["Only alphabetical letters and spaces: no"]
Only alphabetical letters and spaces: yes
EDIT 2: Judging from your new comments, you need something like this:
def hasSpaceAndAlpha[string]:
return any[char.isalpha[] for char in string] and any[char.isspace[] for char in string] and all[char.isalpha[] or char.isspace[] for char in string]
>>> hasSpaceAndAlpha["text# "]
False
>>> hasSpaceAndAlpha["text"]
False
>>> hasSpaceAndAlpha["text "]
True
or
def hasSpaceAndAlpha[string]:
if any[char.isalpha[] for char in string] and any[char.isspace[] for char in string] and all[char.isalpha[] or char.isspace[] for char in string]:
print["Only alphabetical letters and spaces: yes"]
else:
print["Only alphabetical letters and spaces: no"]
>>> hasSpaceAndAlpha["text# "]
Only alphabetical letters and spaces: no
>>> hasSpaceAndAlpha["text"]
Only alphabetical letters and spaces: no
>>> hasSpaceAndAlpha["text "]
Only alphabetical letters and spaces: yes
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Sometimes, while testing of credibility of string being a part of containing just alphabets, an exception of spaces has to be mentioned explicitly and becomes a problem. This can occur in domains that deal with data. Lets discuss certain ways in which this task can be performed.
Method #1 : Using all[] + isspace[] + isalpha[]
This is one of the way in which this task can be performed. In this, we compare the string for all elements being alphabets or space only.
Python3
import re
test_str = 'geeksforgeeks is best for geeks'
print["The original string is : " +
test_str]
res = test_str != '' and all[chr.isalpha[] or chr.isspace[] for chr in test_str]
print["Does String contain only space and alphabets : " + str[res]]
Output :
The original string is : geeksforgeeks is best for geeks Does String contain only space and alphabets : True
Method #1 : Using regex
This problem can also be solved by employing regex to include only space and alphabets in a string.
Python3
import re
test_str = 'geeksforgeeks is best for geeks'
print["The original string is : " + test_str]
res = bool[re.match['[a-zA-Z\s]+$', test_str]]
print["Does String contain only space and alphabets : " + str[res]]
Output :
The original string is : geeksforgeeks is best for geeks Does String contain only space and alphabets : True
The Time and Space Complexity for all the methods are the same:
Time Complexity: O[n]
Auxiliary Space: O[n]