Harry August 28, 2022 Nội dung chính
Author: Harry
Hello friends, thanks for visiting my website. I am a Python programmer. I, with some other members, write blogs on this website based on Python and Programming. We are still in the growing phase that's why the website design is not so good and there are many other things that need to be corrected in this website but I hope all these things will happen someday. But, till then we will not stop ourselves from uploading more amazing articles. If you want to join us or have any queries, you can mail me at Thank you
Author: Harry
Hello friends, thanks for visiting my website. I am a Python programmer. I, with some other members, write blogs on this website based on Python and Programming. We are still in the growing phase that's why the website design is not so good and there are many other things that need to be corrected in this website but I hope all these things will happen someday. But, till then we will not stop ourselves from uploading more amazing articles. If you want to join us or have any queries, you can mail me at Thank you
Exam scores
Captain Holt has corrected the exam papers of detectives and noted the scores of the written and physical tests. The results were posted in two lists: one with the scores of the written test, the other with the scores of the physical test in order of the badge numbers. The office needs a list containing the detectives scores on both tests in order of their badge numbers.
Input:
First line of input contains the score of students in chemistry exam seperated by comma.
Second line of the input contains the score of students in English exam seperated by comma.
Output:
Every line of output contains the score obtained by each student in English and Chemistry exams separated by space.
Sample input:
65
75
Sample output:
75 65
Sample input:
85,88,78
85,86,84
Sample output:
85 85
86 88
84 78
chemistry_scores = list[map[int, input[].split[',']]]
english_scores = list[map[int, input[].split[',']]]
for i in range[len[chemistry_scores]]:
print[english_scores[i], chemistry_scores[i]]Learn more about our help with Assignments: Python
Find Power of Number
Nội dung chính
- How do you find the power of a number in Python?
- How do you check if a number is a power of another number using recursion in Python?
- Is AssignmentExpert com legit?
This Program name is Find Power of Number. Write a Python program to Find Power of Number, it has two test cases
The below link contains Find Power of Number question, explanation and test cases
//drive.google.com/file/d/1vDqKtEIKkaYkLdD_0hwA5rRycaPlBrvG/view?usp=sharing
We need exact output when the code was run
n = int[input[]]
m = int[input[]]
foo = 1
for i in range[m]:
foo *= n
print[foo]
Input 1:
2
3
Output 1:
8
Input 2:
3
1
Output 2:
3Learn more about our help with Assignments: Python
Sum of K powers
Write a program to print the sum of the
The first line of input is an integer
In the given example, the sum of first
5 natural numbers power of 3.The sum should be 13 + 23 + 33 + 43 + 53
Therefore, the output should be
225.
N=int[input[]]
K=int[input[]]
sumResult=0
for number in range[1,N+1]:
sumResult+=pow[number,K]
print[sumResult]
Learn more about our help with Assignments: Python
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Given a number N and power P. The task is to write a Python program to find the power of a number using recursion.
Definition: The power of a number can be defined as multiplication of the number repetitively the number of times of its power.
Example:
Input: N=2 , P=3
Output: 8
Input: N=5 , P=2
Output: 25
Approach: The idea is to calculate power of a number ‘N’ is to multiply that number ‘P’ times i.e In first example N=2 and P=3, we are getting the result by multiplying 2 three times repetitively which gives us output 8.
Below is the implementation:
Python
def power[N, P]:
if P == 0:
return 1
return [N*power[N, P-1]]
N = 5
P = 0
print[power[N, P]]
import numpy as np
print['']
print["Enter two numbers, low then high."]
l = int[input["low = "]]
h = int[input["high = "]]
def binarySearch [arr, l, r, num]:
if r >= l:
mid = l + [r - l] // 2
print["Is your number Less than, Greater than, or Equal to {0}?".format[arr[mid]]]
while True:
x = str[input["Type 'L', 'G' or 'E':"]]
if x in ['L', 'G', 'E', 'l', 'g', 'e']:
break
print['']
if x == 'E' or x == 'e':
num = num + 1
if num == 1:
print["I found your number in 1 guess."]
else :
print["Your number is {0}. I found it in {1} guesses.".format[arr[mid], num]]
elif x == 'L' or x == 'l':
num = num + 1
return binarySearch[arr, l, mid-1, num]
else:
num = num + 1
return binarySearch[arr, mid + 1, r, num]
else:
print["Your answers have not been consistent."]
while l>h:
print['']
print["Please enter the smaller followed by the larger number."]
l = int[input["low = "]]
h = int[input["high = "]]
print['']
print["Think of a number in the range {0} to {1}.".format[l, h]]
print['']
if l == h:
print["Your number is {0}. I found it in 0 guesses.".format[l]]
else :
arr = np.arange[l+1, h]
binarySearch[arr, 0, len[arr]-1, 0]How do you find the power of a number in Python?
How to find the power of a number in Python.
import math. print[math. pow[4,2]] Run. Importing math module in Python..
def power[n,e]: res=0. for i in range[e]: res *= n. return res. print[pow[4,2]] Run. ... .
def power[n, e]: if e == 0: return 1. elif e == 1: return n. else: return [n*power[n, e-1]].
How do you check if a number is a power of another number using recursion in Python?
“if number is power of base in python recursion” Code Answer.
def power[base,exp]:.
if[exp==1]:.
return[base].
if[exp!=1]:.
return[base*power[base,exp-1]].
base=int[input["Enter base: "]].
exp=int[input["Enter exponential value: "]].
print["Result:",power[base,exp]].
Is AssignmentExpert com legit?
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