Get directory from file path javascript

How to get the directory of a file?

For example, I pass in a string

C:\Program Files\nant\bin\nant.exe

I want a function that returns me

C:\Program Files\nant\bin

I would prefer a built in function that does the job, instead of having manually split the string and exclude the last one.

Edit: I am running on Windows

asked May 4, 2009 at 2:10

GravitonGraviton

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I don't know if there is any built in functionality for this, but it's pretty straight forward to get the path.

path = path.substring[0,path.lastIndexOf["\\"]+1];

Abyx

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answered May 4, 2009 at 2:19

PhaedrusPhaedrus

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If you use Node.js, path module is quite handy.

path.dirname["/home/workspace/filename.txt"] // '/home/workspace/'

Zanon

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answered Mar 21, 2020 at 12:34

W.PerrinW.Perrin

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Use:

var dirname = filename.match[/[.*][\/\\]/][1]||'';

*The answers that are based on lastIndexOf['/'] or lastIndexOf['\'] are error prone, because path can be "c:\aa/bb\cc/dd".
[Matthew Flaschen did took this into account, so my answer is a regex alternative]

answered Aug 20, 2015 at 17:27

TheZverTheZver

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There's no perfect solution, because this functionality isn't built-in, and there's no way to get the system file-separator. You can try:

path = path.substring[0, Math.max[path.lastIndexOf["/"], path.lastIndexOf["\\"]]]; 
alert[path];

Abyx

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answered May 4, 2009 at 2:35

Matthew FlaschenMatthew Flaschen

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Path module has an inbuilt function

Yes, the inbuilt module path has dirname[] function, which would do the job for you.

const path = require["path"];

file_path = "C:\\Program Files\\nant\\bin\\nant.exe" \\windows path
file_path = "C:/Program Files/nant/bin/nant.exe" \\linux path

path.dirname[file_path]; \\gets you the folder path based on your OS

I see that your path is neither windows nor Linux compatible. Do not hardcode path; instead, take a reference from a path based on your OS.

I generally tackle such situations by creating relative paths using path.join[__dirname, "..", "assets", "banner.json"];.

This gives me a relative path that works regardless of the OS you are using.

answered Nov 30, 2021 at 7:21

function getFileDirectory[filePath] {
  if [filePath.indexOf["/"] == -1] { // windows
    return filePath.substring[0, filePath.lastIndexOf['\\']];
  } 
  else { // unix
    return filePath.substring[0, filePath.lastIndexOf['/']];
  }
}
console.assert[getFileDirectory['C:\\Program Files\\nant\\bin\\nant.exe'] === 'C:\\Program Files\\nant\\bin'];
console.assert[getFileDirectory['/usr/bin/nant'] === '/usr/bin'];

answered May 4, 2009 at 2:47

brianpeirisbrianpeiris

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Sorry to bring this back up but was also looking for a solution without referencing the variable twice. I came up with the following:

var filepath = 'C:\\Program Files\\nant\\bin\\nant.exe';
    // C:\Program Files\nant\bin\nant.exe
var dirpath = filepath.split['\\'].reverse[].splice[1].reverse[].join['\\'];
    // C:\Program Files\nant\bin

This is a bit of a walk through manipulating a string to array and back but it's clean enough I think.

answered Jan 22, 2016 at 21:18

SmujMaikuSmujMaiku

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And this?

If isn't a program in addressFile, return addressFile

function[addressFile] {
    var pos = addressFile.lastIndexOf["/"];
    pos = pos != -1 ? pos : addressFile.lastIndexOf["\\"];

    if [pos > addressFile.lastIndexOf["."]] {
        return addressFile;
    }

    return addressFile.substring[
        0,
        pos+1
    ];
}


console.assert[getFileDirectory['C:\\Program Files\\nant\\bin\\nant.exe'] === 'C:\\Program Files\\nant\\bin\\'];
console.assert[getFileDirectory['/usr/bin/nant'] === '/usr/bin/nant/'];
console.assert[getFileDirectory['/usr/thisfolderhaveadot.inhere'] === '/usr/'];

answered Mar 30, 2014 at 21:28

filepath.split["/"].slice[0,-1].join["/"]; // get dir of filepath

1. split string into array delimited by "/"
2. drop the last element of the array [which would be the file name + extension]
3. join the array w/ "/" to generate the directory path

such that

"/path/to/test.js".split["/"].slice[0,-1].join["/"] == "/path/to"

answered May 20, 2018 at 16:45

Ulad KasachUlad Kasach

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The core Javascript language doesn't provide file/io functions. However if you're working in a Windows OS you can use the FileSystemObject [ActiveX/COM].

Note: Don't use this in the client script-side script of a web application though, it's best in other areas such as in Windows script host, or the server side of a web app where you have more control over the platform.

This page provides a good tutorial on how to do this.

Here's a rough example to do what you want:

   var fso, targetFilePath,fileObj,folderObj;

   fso = new ActiveXObject["Scripting.FileSystemObject"];

   fileObj = fso.GetFile[targetFilePath];

   folderObj=fileObj.ParentFolder;

   alert[folderObj.Path];

Graviton

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answered May 4, 2009 at 2:17

AshAsh

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6

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