Na2 fe cn 5.no 2h2o là chất gì năm 2024

Mô tả chi tiết

- Chất không hòa tan ≤ 0,01% - Clorua (Cl) ≤ 0,02% - Hexacyanoferrate (II) ≤ 0,02% - Hexacyanoferrate (III) ≤ 0,01% - Sulfate (SO₄) ≤ 0,01% - Hình thể: rắn, màu đỏ - Khối lượng mol: 297.95 g/mol - Mật độ: 1,71 g / cm3 (20°C) - Giá trị pH: 5 (50 g / l, H₂O, 20°C) - Mật độ lớn: 1000 kg/m3 - Độ hòa tan: 400 g/l (phân hủy chậm) - Bảo quản dưới +30°C. - Hóa chất dùng làm thuốc thử trong phân tích và chuẩn bị mẫu, dùng trong phân tích dược phẩm. Sử dụng rộng rãi tại các phòng thí nghiệm trường học, viện nghiên cứu,...

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Solution

Let x be the oxidation number of Fe.

The oxidation numbers of Na+, CN− ion and NO group are +1,−1 and 0 respectively. The sum of the oxidation numbers is zero as the compound is neutral. Hence, 2(+1)+x+5(−1)+0\=0 or, x\=+3. The oxidation state of iron in Na2[Fe(CN)5(NO)].2H2O is +3.

Q1

Calculate the oxidation number of underlined element in the following compound: Na2[Fe−(CN)5(NO+)]

Q2

What is the oxidation state of iron (Fe) in [Fe(CN)5NO]2−? [Note: Write the correct answer in modulus of oxidation state]

Q3

Oxidation state of iron in Na2[Fe(CN)5(NO)] is:

Q4

Find the oxidation number of Fe in Na2[Fe(CN)5NO].

Q5

In Na2[Fe(CN)5NO] sodium nitroprusside ___________.