Create a list of 100 integers whose value and index are the same, e.g.
mylist[0] = 0, mylist[1] = 1, mylist[2] = 2, ...
Here is my code.
x_list=[]
def list_append[x_list]:
for i in 100:
x_list.append[i]
return[list_append[]]
print[x_list]
Veedrac
55.7k14 gold badges108 silver badges165 bronze badges
asked Sep 26, 2013 at 3:49
2
Since nobody else
realised you're using Python 3, I'll point out that you should be doing list[range[100]]
to get the wanted behaviour.
answered Sep 26, 2013 at 4:22
VeedracVeedrac
55.7k14 gold badges108 silver badges165 bronze badges
2
Use range[] for generating such a list
>>> range[10]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> range[10][5]
5
answered Sep 26, 2013 at 3:50
for i in 100
doesn't do what you think it does. int
objects are not iterable, so this won't work. The for-loop tries to iterate through the object given.
If you want to get a list of numbers
between 0-100, use range[]
:
for i in range[100]:
dostuff[]
The answer to your question is pretty much range[100]
anyway:
>>> range[100][0]
0
>>> range[100][64]
64
answered Sep 26, 2013 at 3:50
TerryATerryA
56.9k11 gold badges117 silver badges137 bronze badges
You can use range[100]
, but it seems that you are probably looking to make the list from scratch, so there you can use while
:
x_list=[]
i = 0
while i