How do you print if a number is odd or even in python?
A number is even if it is perfectly divisible by 2. When the number is divided by 2, we use the remainder operator Show
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Output 1 Enter a number: 43 43 is Odd Output 2 Enter a number: 18 18 is Even In this program, we ask the user for the input and check if the number is odd or even. Please note that Python Program to Check if a Number is Odd or EvenOdd and Even numbers: If you divide a number by 2 and it gives a remainder of 0 then it is known as even number, otherwise an odd number. Even number examples: 2, 4, 6, 8, 10, etc. Odd number examples:1, 3, 5, 7, 9 etc. See this example: Output: For Videos Join Our Youtube Channel: Join Now Feedback
Help Others, Please SharePython Basic: Exercise-21 with SolutionWrite a Python program to find whether a given number (accept from the user) is even or odd, print out an appropriate message to the user. Pictorial Presentation of Even Numbers: Pictorial Presentation of Odd Numbers: Sample Solution:- Python Code:
Sample Output: Enter a number: 5 This is an odd number. Even Numbers between 1 to 100: Odd Numbers between 1 to 100: Flowchart: Visualize Python code execution:The following tool visualize what the computer is doing step-by-step as it executes the said program: Python Code Editor: Have another way to solve this solution? Contribute your code (and comments) through Disqus. Previous: Write a Python program to get a string which is n (non-negative integer) copies of a given string. Python: Tips of the DayConvert a dict to XML: from xml.etree.ElementTree import Elementdef dict_to_xml(tag, d): ''' Turn a simple dict of key/value pairs into XML ''' elem = Element(tag) for key, val in d.items(): child = Element(key) child.text = str(val) elem.append(child) return elem I'm trying to make a program which checks if a word is a palindrome and I've gotten so far and it works with words that have an even amount of numbers. I know how to make it do something if the amount of letters is odd but I just don't know how to find out if a number is odd. Is there any simple way to find if a number is odd or even? Just for reference, this is my code:
mkrieger1 15.6k4 gold badges45 silver badges57 bronze badges asked Feb 17, 2014 at 19:03
1
The Or reverse them for a little speed improvement, since any number above 0 is also considered "True" you can skip needing to do any equality check:
answered Feb 17, 2014 at 19:05
DeadChexDeadChex 4,2531 gold badge25 silver badges33 bronze badges 5 Similarly to other languages, the fastest "modulo 2" (odd/even) operation is done using the
Using Bitwise AND operator
answered Feb 17, 2014 at 19:07
lejlotlejlot 62.7k8 gold badges128 silver badges158 bronze badges 6 It shouldn't matter if the word has an even or odd amount fo letters:
answered Feb 17, 2014 at 19:05
kylieCattkylieCatt 10.3k5 gold badges40 silver badges51 bronze badges 3 One of the simplest ways is to use de modulus operator %. If n % 2 == 0, then your number is even. Hope it helps, answered Feb 17, 2014 at 19:05
Esteban AlivertiEsteban Aliverti 6,0792 gold badges18 silver badges31 bronze badges Use the modulo operator:
For your problem, the simplest is to check if the word is equal to its reversed brother. You can do that with
answered Feb 17, 2014 at 19:05
Maxime LorantMaxime Lorant 32.5k18 gold badges84 silver badges96 bronze badges 0 The middle letter of an odd-length word is irrelevant in determining whether the word is a palindrome. Just ignore it. Hint: all you need is a slight tweak to the following line to make this work for all word lengths:
P.S. If you insist on handling the two cases separately, answered Feb 17, 2014 at 19:05
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