How to get last year date in php?

How am I able to get the value of the previous year using PHP. Are there any predefined functions for it?

wattostudios

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asked May 5, 2011 at 10:37

2

try

echo date("Y",strtotime("-1 year"));

answered May 5, 2011 at 10:47

diEchodiEcho

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1

There are many ways, you can either take away the amount of seconds in a year from time() like so:

$prevYear = date('Y', time() - 60*60*24*365 );

Or if you'd prefer, use the PHPs clever strtotime() function:

$prevYear = date('Y', strtotime('-1 year'));

Or even like others have said, if it's from todays year just do date('Y') -1

answered May 5, 2011 at 10:45

DunhamzzzDunhamzzz

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1

Shortest approach:

$lastYear = (int)date("Y") - 1;

answered Sep 25, 2017 at 10:33

michal.jakubeczymichal.jakubeczy

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1

function adddate($vardate,$added)
{
$data = explode("-", $vardate);
$date = new DateTime();            
$date->setDate($data[0], $data[1], $data[2]);
$date->modify("".$added."");
$day= $date->format("Y-m-d");
return $day;    
}

echo "Example : " . adddate("2010-08-01","-1 year");

answered May 5, 2011 at 10:44

jimyjimy

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you can give a value of the input tag as :

answered Jun 27, 2019 at 22:28

0

If you want to display the entire date exactly 1 year ago, including the month and year:

Kirk Beard

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answered Jan 24, 2013 at 14:56

Midnightly CoderMidnightly Coder

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answered Mar 31 at 5:26

Try This

date('Y', strtotime('last year'));

answered Nov 7, 2017 at 9:56

This thread needs an update.

Nowadays you would use the PHP date-time object and do something like this:

$lastYear = new DateTime();
$lastYear->sub(new DateInterval('P1Y'));
echo $lastYear->format('Y');

answered Apr 25, 2020 at 17:20

HappyCoderHappyCoder

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