Hướng dẫn bitwise operators program in php - chương trình toán tử bitwise trong php
Xem thảo luận Show Cải thiện bài viết Lưu bài viết Xem thảo luận Cải thiện bài viết Lưu bài viết
>> (BitWise Shift Shift): Đây cũng là toán tử nhị phân, tức là hoạt động trên hai toán hạng. Toán tử BitWise Shift có hai số, phải thay đổi các bit của toán hạng đầu tiên, toán hạng thứ hai quyết định số lượng địa điểm thay đổi. Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)3 Lưu ý: Bitwise Shift bên phải với một bit tương đương với phân chia với 2. Dưới đây là việc triển khai các toán tử bitwise trong PHP: Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)5 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)6 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)8 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)9 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)3 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.1 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.2 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)5 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.4 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)8 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.6 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 $First ^ $Second This will return another number whose bits are set if one of the bit in first or second is set but not both.4 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)3 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.9 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 3 Output: The bitwise ^ of both these value will be 6. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise ^ will be 0110 (i.e. set if either first or second have their bit set but not both.)9 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)3 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.1 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.22 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)5 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)9 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)8 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.6 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: number = 5 Output: The bitwise '~' of this number will be -6. Explanation: Binary representation of 5 is 0101. Therefore the bitwise ~ of this will be 1010 (inverts all the bits of the input number)2 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)3 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.1 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.2 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)5 Input: First = 5, Second = 3 Output: The bitwise ^ of both these value will be 6. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise ^ will be 0110 (i.e. set if either first or second have their bit set but not both.)4 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)8 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.6 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.1 ~$number This will invert all the bits of $number.7 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)5 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.6 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 1 Output: The bitwise << of both these value will be 10. Explanation: Binary representation of 5 is 0101 . Therefore, bitwise << will shift the bits of 5 one times towards the left (i.e. 01010 )0 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)3 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)8 $First << $Second This will shift the bits of $First towards the left. $Second decides the number of time the bits will be shifted.0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)05 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)4 $First | $Second This will return another number whose bits are set if either the bit of first or second are set.8 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)3 Input: First = 5, Second = 3 Output: The bitwise | of both these value will be 7. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise | will be 0111 (i.e. set if either first or second have their bit set.)0 Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)11 Output: Input: $First = 5, $Second = 3 Output: The bitwise & of both these value will be 1. Explanation: Binary representation of 5 is 0101 and 3 is 0011. Therefore their bitwise & will be 0001 (i.e. set if both first and second have their bit set.)2 Các toán tử bitwise trong PHP là gì?Các toán tử bitwise được sử dụng để thực hiện các hoạt động cấp độ bit trên các toán hạng.Các toán tử trước tiên được chuyển đổi thành cấp độ bit và sau đó tính toán được thực hiện trên các toán hạng.Các hoạt động toán học như bổ sung, trừ, nhân, v.v.used to perform bit-level operations on the operands. The operators are first converted to bit-level and then calculation is performed on the operands. The mathematical operations such as addition , subtraction , multiplication etc.
Ví dụ về toán tử bitwise là gì?Các loại toán tử bitwise trong C. Nhà điều hành trong PHP với ví dụ là gì?Các toán tử số học PHP. |