Hướng dẫn dùng pd.dataframe.from_dict python
Construct DataFrame from dict of array-like or dicts. Creates DataFrame object from dictionary by columns or by index allowing dtype specification. ParametersdatadictOf the form {field : array-like} or {field : dict}. orient{‘columns’, ‘index’, ‘tight’}, default ‘columns’The “orientation” of the data. If the keys of the passed dict should be the columns of the resulting DataFrame, pass ‘columns’ (default). Otherwise if the keys should be rows, pass ‘index’. If ‘tight’, assume a dict with keys [‘index’, ‘columns’, ‘data’, ‘index_names’, ‘column_names’]. New in version 1.4.0: ‘tight’ as an allowed value for the Data type to force, otherwise infer. columnslist, default NoneColumn labels to use when Examples By default the keys of the dict become the DataFrame columns: >>> data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']} >>> pd.DataFrame.from_dict(data) col_1 col_2 0 3 a 1 2 b 2 1 c 3 0 d Specify >>> data = {'row_1': [3, 2, 1, 0], 'row_2': ['a', 'b', 'c', 'd']} >>> pd.DataFrame.from_dict(data, orient='index') 0 1 2 3 row_1 3 2 1 0 row_2 a b c d When using the ‘index’ orientation, the column names can be specified manually: >>> pd.DataFrame.from_dict(data, orient='index', ... columns=['A', 'B', 'C', 'D']) A B C D row_1 3 2 1 0 row_2 a b c d Specify >>> data = {'index': [('a', 'b'), ('a', 'c')], ... 'columns': [('x', 1), ('y', 2)], ... 'data': [[1, 3], [2, 4]], ... 'index_names': ['n1', 'n2'], ... 'column_names': ['z1', 'z2']} >>> pd.DataFrame.from_dict(data, orient='tight') z1 x y z2 1 2 n1 n2 a b 1 3 c 2 4 |