Hướng dẫn is there a sum method in python? - có một phương thức tổng trong python?

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Syntax:

sum(iterable, start)  
iterable : iterable can be anything list , tuples or dictionaries ,
 but most importantly it should be numbers.
start : this start is added to the sum of 
numbers in the iterable. 
If start is not given in the syntax , it is assumed to be 0.

Bàn luận

sum(a)
a is the list , it adds up all the numbers in the 
list a and takes start to be 0, so returning 
only the sum of the numbers in the list.
sum(a, start)
this returns the sum of the list + start 

Tổng số trong danh sách được yêu cầu ở mọi nơi. Python cung cấp một tổng số hàm sẵn () tổng hợp các số trong danh sách. & Nbsp;

Python3

sum(iterable, start)

sum(iterable, start)

sum(iterable, start)

sum(iterable, start)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)
print(numbers_sum)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)
print(numbers_sum)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)
print(numbers_sum)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)




print(numbers_sum)

4.5
14.5

sum(iterable, start)

4.5
14.5

4.5
14.5

4.5
14.5

'string'.join(sequence)

4.5
14.5

'string'.join(sequence)

Có thể hai cú pháp:

Dưới đây là việc triển khai Python của SUM () & NBSP;

Output:

25
35

4.5
14.5

sum(iterable, start)

4.5
14.5

'string'.join(sequence)

'string'.join(sequence)

'string'.join(sequence)

4.5
14.5

'string'.join(sequence)

4.5
14.5

'string'.join(sequence)

Python3

Lỗi và ngoại lệ

4.5
14.5

sum(iterable, start)

4.5
14.5

sum(iterable, start)  
iterable : iterable can be anything list , tuples or dictionaries ,
 but most importantly it should be numbers.
start : this start is added to the sum of 
numbers in the iterable. 
If start is not given in the syntax , it is assumed to be 0.

4.5
14.5

'string'.join(sequence)

4.5
14.5

'string'.join(sequence)

4.5
14.5

sum(iterable, start)

4.5
14.5

sum(a)
a is the list , it adds up all the numbers in the 
list a and takes start to be 0, so returning 
only the sum of the numbers in the list.
sum(a, start)
this returns the sum of the list + start 

'string'.join(sequence)

'string'.join(sequence)

4.5
14.5

'string'.join(sequence)

4.5
14.5

'string'.join(sequence)

Lỗi runtime :

Python3

sum(iterable, start)

sum(iterable, start)

sum(iterable, start)

sum(iterable, start)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)
print(numbers_sum)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)
print(numbers_sum)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)
print(numbers_sum)

numbers = [2.5, 3, 4, -5]

# start parameter is not provided
numbers_sum = sum(numbers)
print(numbers_sum)

# start = 10
numbers_sum = sum(numbers, 10)
print(numbers_sum)

4.5
14.5

sum(iterable, start)

4.5
14.5

4.5
14.5

3

sum(iterable, start)

4.5
14.5

sum(iterable, start)

sum(iterable, start)

4.5
14.5

4.5
14.5

sum(iterable, start)

Output:

3