I have some escaped strings that need to be unescaped. I'd like to do this in Python.
For example, in Python 2.7 I can do this:
>>> "\\123omething special".decode['string-escape']
'Something special'
>>>
How do I do it in Python 3? This doesn't work:
>>> b"\\123omething special".decode['string-escape']
Traceback [most recent call last]:
File "", line 1, in
LookupError: unknown encoding: string-escape
>>>
My goal is to be able to take a string like this:
s\000u\000p\000p\000o\000r\000t\000@\000p\000s\000i\000l\000o\000c\000.\000c\000o\000m\000
And turn it into:
""
After I do the conversion, I'll probe to see if the string I have is encoded in UTF-8 or UTF-16.
SuperStormer
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asked Feb 11, 2013 at 20:37
3
You'll have to use unicode_escape
instead:
>>> b"\\123omething special".decode['unicode_escape']
If you start with a str
object instead [equivalent to the python 2.7 unicode] you'll need to encode to bytes first, then decode with unicode_escape
.
If
you need bytes as end result, you'll have to encode again to a suitable encoding [.encode['latin1']
for example, if you need to preserve literal byte values; the first 256 Unicode code points map 1-on-1].
Your example is actually UTF-16 data with escapes. Decode from unicode_escape
, back to latin1
to preserve the bytes, then from utf-16-le
[UTF 16 little endian without BOM]:
>>> value = b's\\000u\\000p\\000p\\000o\\000r\\000t\\000@\\000p\\000s\\000i\\000l\\000o\\000c\\000.\\000c\\000o\\000m\\000'
>>> value.decode['unicode_escape'].encode['latin1'] # convert to bytes
b's\x00u\x00p\x00p\x00o\x00r\x00t\x00@\x00p\x00s\x00i\x00l\x00o\x00c\x00.\x00c\x00o\x00m\x00'
>>> _.decode['utf-16-le'] # decode from UTF-16-LE
''
answered Feb 11, 2013 at 20:40
Martijn Pieters♦Martijn Pieters
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4
The old "string-escape" codec maps bytestrings to bytestrings, and there's been a lot of debate about what to do with such codecs, so it isn't currently available through the standard encode/decode interfaces.
BUT, the code is still there in the C-API [as PyBytes_En/DecodeEscape
], and this is still exposed to Python via the undocumented codecs.escape_encode
and codecs.escape_decode
.
>>> import codecs
>>> codecs.escape_decode[b"ab\\xff"]
[b'ab\xff', 6]
>>> codecs.escape_encode[b"ab\xff"]
[b'ab\\xff', 3]
These functions return the transformed bytes
object, plus a number indicating how
many bytes were processed... you can just ignore the latter.
>>> value = b's\\000u\\000p\\000p\\000o\\000r\\000t\\000@\\000p\\000s\\000i\\000l\\000o\\000c\\000.\\000c\\000o\\000m\\000'
>>> codecs.escape_decode[value][0]
b's\x00u\x00p\x00p\x00o\x00r\x00t\x00@\x00p\x00s\x00i\x00l\x00o\x00c\x00.\x00c\x00o\x00m\x00'
answered Apr 18, 2014 at 9:57
1
If you want str-to-str decoding of escape sequences, so both input and output are Unicode:
def string_escape[s, encoding='utf-8']:
return [s.encode['latin1'] # To bytes, required by 'unicode-escape'
.decode['unicode-escape'] # Perform the actual octal-escaping decode
.encode['latin1'] # 1:1 mapping back to bytes
.decode[encoding]] # Decode original encoding
Testing:
>>> string_escape['\\123omething special']
'Something special'
>>> string_escape[r's\000u\000p\000p\000o\000r\000t\000@'
r'\000p\000s\000i\000l\000o\000c\000.\000c\000o\000m\000',
'utf-16-le']
''
answered Nov 13, 2019 at 2:33
MestreLionMestreLion
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3
You can't use unicode_escape
on byte strings [or rather, you can, but it doesn't always return the same thing as string_escape
does on Python 2] – beware!
This function implements string_escape
using a regular expression and custom replacement logic.
def unescape[text]:
regex = re.compile[b'\\\\[\\\\|[0-7]{1,3}|x.[0-9a-f]?|[\'"abfnrt]|.|$]']
def replace[m]:
b = m.group[1]
if len[b] == 0:
raise ValueError["Invalid character escape: '\\'."]
i = b[0]
if i == 120:
v = int[b[1:], 16]
elif 48