Regex for percentage with 2 decimal places javascript
Is there a regex that would validate a percentage value to 2 decimal places? I have a regex for two decimal places, but don't know how to stop values above 100. e.g. 100.01 is validated with my regex.
DVK 125k31 gold badges208 silver badges321 bronze badges asked Sep 14, 2009 at 14:51
littlechrislittlechris 4,12410 gold badges42 silver badges66 bronze badges 5 In Perl:
or you can just add an extra if comparing 100 exactly :)
Syscall 18.3k10 gold badges33 silver badges49 bronze badges answered Sep 14, 2009 at 14:55
7 This allows all percentages except zero.
answered Apr 18, 2017 at 12:43
NarayanaNarayana 1051 silver badge8 bronze badges 1 Try this one:
That gives you a one digit or two digit number followed by exactly two decimal places. If you want to allow tenths as well (ala 10.1) then try this:
answered Sep 14, 2009 at 14:56
Tony MillerTony Miller 8,9792 gold badges26 silver badges46 bronze badges 2 Try this one (accepts anything between 0 and 100 including 0.00 & 100.00:
answered May 13, 2013 at 15:31
use this regex for validate the percentage in the angular project or javascript project
Syscall 18.3k10 gold badges33 silver badges49 bronze badges answered Mar 12, 2021 at 9:28
Works with:
etc.
Syscall 18.3k10 gold badges33 silver badges49 bronze badges answered Sep 14, 2009 at 15:00
XetiusXetius 42.9k24 gold badges83 silver badges119 bronze badges Keywords Change page: | Displaying page 2 of 2 pages; Items 21 to 32
Change page: | Displaying page 2 of 2 pages; Items 21 to 32 How do you find a percentage to 2 decimal places?Suppose your score is 57.114. So, when you want to round it off just write 57.11 as the last digit 4 is less than 5. If your score is 57.118, then as per the rule of rounding of the digits the last digit 8 is greater than 5. So we write the score as 57.12 by increasing 1 to the last digit of the two decimal place.
How do you write a decimal number in regex?One or more digits ( \d+ ), optional period ( \.? ), zero or more digits ( \d* ).
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