Count consonants in a string javascript

The main problem in counts lies within your conditions.

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How do you calculate the number of vowels and consonants in a string JavaScript?
How do you count the number of consonants in a string in Java?
How do I count strings in JavaScript?
How do you count the number of vowels and consonants in a string?

You're increasing the number of consonants whenever one of the conditions fail (that's what || does, known as the OR operator). So whenever a character !== "a" OR !== "e", you're increasing the count, which is wrong. (Imagine that a is !== 'e', so you're counting a as a consonant).

Change the || binary operator to && (AND); this way, you're only increasing the consonant count whenever the current character str[i] is not among the values you're verifying for (a, e, i, o, u, ' ').

As others pointed out, you're also likely to run into an error as the max value of i should be Length-1.

There also other problems you need to consider:

What happens when the character is an uppercase letter?
What happens when the character is a punctuation mark or a number?

For a beginner, this may not be relevant, but it's well worth getting these techniques under your skin: It's more readable to create an array that contains all of the value you're verifying for ["a","e", etc] and then, for each char in the source string, just verify if array.indexOf(str[i]) >= 0 (which means that the character is included in the array).

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Given a string, count total number of consonants in it. A consonant is a English alphabet character that is not vowel (a, e, i, o and u). Examples of constants are b, c, d, f, g, ..

Examples :

Input : abc de
Output : 3
There are three consonants b, c and d.

Input : geeksforgeeks portal
Output : 12

1. Iterative Method

C++

#include

using namespace std;

bool isConsonant(char ch)

{

ch = toupper(ch);

return !(ch == 'A' || ch == 'E' ||

ch == 'I' || ch == 'O' ||

ch == 'U') && ch >= 65 && ch <= 90;

}

int totalConsonants(string str)

{

int count = 0;

for (int i = 0; i < str.length(); i++)

if (isConsonant(str[i]))

++count;

return count;

}

int main()

{

string str = "abc de";

cout << totalConsonants(str);

return 0;

}

Java

import java.io.*;

class GFG {

static boolean isConsonant(char ch)

{

ch = Character.toUpperCase(ch);

return !(ch == 'A' || ch == 'E' ||

ch == 'I' || ch == 'O' ||

ch == 'U') && ch >= 65 && ch <= 90;

}

static int totalConsonants(String str)

{

int count = 0;

for (int i = 0; i < str.length(); i++)

if (isConsonant(str.charAt(i)))

++count;

return count;

}

public static void main(String args[])

{

String str = "abc de";

System.out.println( totalConsonants(str));

}

Python3

def isConsonant(ch):

ch = ch.upper()

return not (ch == 'A' or ch == 'E' or

ch == 'I' or ch == 'O' or

ch == 'U') and ord(ch) >= 65 and ord(ch) <= 90

def totalConsonants(string):

count = 0

for i in range(len(string)):

if (isConsonant(string[i])):

count += 1

return count

string = "abc de"

print(totalConsonants(string))

C#

using System;

class GFG {

static bool isConsonant(char ch)

{

ch = Char.ToUpper(ch);

return !(ch == 'A' || ch == 'E' ||

ch == 'I' || ch == 'O' ||

ch == 'U') && ch >= 65 && ch <= 90;

}

static int totalConsonants(String str)

{

int count = 0;

for (int i = 0; i < str.Length; i++)

if (isConsonant(str[i]))

++count;

return count;

}

public static void Main()

{

String str = "abc de";

Console.Write( totalConsonants(str));

}

PHP

function isConsonant($ch)

{

$ch = strtoupper($ch);

return !($ch == 'A' || $ch == 'E' ||

$ch == 'I' || $ch == 'O' ||

$ch == 'U') && ord($ch) >= 65 && ord($ch) <= 90;

}

function totalConsonants($str)

{

$count = 0;

for ($i = 0; $i < strlen($str); $i++)

if (isConsonant($str[$i]))

++$count;

return $count;

}

$str = "abc de";

echo totalConsonants($str);

return 0;

?>

`Javascript`

function totalConsonants(str) {

var count = 0;

for (var i = 0; i < str.length; i++)

if (isConsonant(str[i])) ++count;

return count;

}

var str = "abc de";

document.write(totalConsonants(str));

Time Complexity: O(n), where n is the length of the string Auxiliary Space: O(1)

2. Recursive Method

`C++`

#include

using namespace std;

bool isConsonant(char ch)

{

ch = toupper(ch);

return !(ch == 'A' || ch == 'E' ||

ch == 'I' || ch == 'O' ||

ch == 'U') && ch >= 65 && ch <= 90;

}

int totalConsonants(string str, int n)

{

if (n == 1)

return isConsonant(str[0]);

return totalConsonants(str, n - 1) +

isConsonant(str[n-1]);

}

int main()

{

string str = "abc de";

cout << totalConsonants(str, str.length());

return 0;

}

`Java`

import java.util.*;

import java.lang.*;

class GFG

{

static boolean isConsonant(char ch)

{

ch = Character.toUpperCase(ch);

return (ch == 'A' || ch == 'E' ||

ch == 'I' || ch == 'O' ||

ch == 'U')== false && ch >= 65 && ch <= 90;

}

static int totalConsonants(String str, int n)

{

if (n == 1)

{

if(isConsonant(str.charAt(0)))

return 1;

else

return 0;

}

if(isConsonant(str.charAt(n - 1)))

return totalConsonants(str, n - 1) + 1;

else

return totalConsonants(str, n - 1);

}

public static void main(String args[])

{

String str = "abc de";

System.out.println(totalConsonants(str, str.length()));

}

`Python3`

def isConsonant(ch):

ch = ch.upper()

return not (ch == 'A' or ch == 'E' or

ch == 'I' or ch == 'O' or

ch == 'U') and ord(ch) >= 65 and ord(ch) <= 90

def totalConsonants(string, n):

if n == 1:

return isConsonant(string[0])

return totalConsonants(string, n - 1) + isConsonant(string[n-1])

string = "abc de"

print(totalConsonants(string, len(string)))

`C#`

using System;

class GFG

{

static Boolean isConsonant(char ch)

{

ch = char.ToUpper(ch);

return (ch == 'A' || ch == 'E' ||

ch == 'I' || ch == 'O' ||

ch == 'U') == false &&

ch >= 65 && ch <= 90;

}

static int totalConsonants(String str, int n)

{

if (n == 1)

{

if(isConsonant(str[0]))

return 1;

else

return 0;

}

if(isConsonant(str[n - 1]))

return totalConsonants(str, n - 1) + 1;

else

return totalConsonants(str, n - 1);

}

public static void Main(String []args)

{

String str = "abc de";

Console.WriteLine(totalConsonants(str, str.Length));

}

`Javascript`

Time Complexity: O(n), where n is the length of the string Auxiliary Space: O(1)

Illustration of recursive method:


 
How do you calculate the number of vowels and consonants in a string JavaScript?
var userData = prompt ("Enter any text here"); var a = 0; var e = 0; var i = 0; var o = 0; var u = 0; var consonants = 0; var count; for (count = 0; count <= userData. legth; count++){ if((userData. charAt(count). match(/[aeiou]/))){ a++; e++; i++; o++; u++; }else if((userData.
How do you count the number of consonants in a string in Java?
To count the number of consonants in a given sentence:.
 Read a sentence from the user..
 Create a variable (count) initialize it with 0;.
 Compare each character in the sentence with the characters {'a', 'e', 'i', 'o', 'u' } If match doesn't occurs increment the count..
 Finally print count..
 
How do I count strings in JavaScript?
In JavaScript, we can count the string occurrence in a string by counting the number of times the string present in the string. JavaScript provides a function match(), which is used to generate all the occurrences of a string in an array.
How do you count the number of vowels and consonants in a string?
#include .
 int main().
 //Counter variable to store the count of vowels and consonant..
 int i, vCount = 0, cCount = 0;.
 char str[] = "This is a really simple sentence";.
 for(i = 0; i < strlen(str); i++){.
 str[i] = tolower(str[i]);.

Count consonants in a string javascript

C++

Java

Python3

C#

PHP

Javascript

C++

Java

Python3

C#

Javascript

How do you calculate the number of vowels and consonants in a string JavaScript?

How do you count the number of consonants in a string in Java?

How do I count strings in JavaScript?

How do you count the number of vowels and consonants in a string?

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