Python median of list numpy

numpy.median(a, axis=None, out=None, overwrite_input=False, keepdims=False)[source]#

Compute the median along the specified axis.

Returns the median of the array elements.

Parametersaarray_like

Input array or object that can be converted to an array.

axis{int, sequence of int, None}, optional

Axis or axes along which the medians are computed. The default is to compute the median along a flattened version of the array. A sequence of axes is supported since version 1.9.0.

outndarray, optional

Alternative output array in which to place the result. It must have the same shape and buffer length as the expected output, but the type (of the output) will be cast if necessary.

overwrite_inputbool, optional

If True, then allow use of memory of input array a for calculations. The input array will be modified by the call to median. This will save memory when you do not need to preserve the contents of the input array. Treat the input as undefined, but it will probably be fully or partially sorted. Default is False. If overwrite_input is True and a is not already an ndarray, an error will be raised.

keepdimsbool, optional

If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the original arr.

New in version 1.9.0.

Returns medianndarray

A new array holding the result. If the input contains integers or floats smaller than float64, then the output data-type is np.float64. Otherwise, the data-type of the output is the same as that of the input. If out is specified, that array is returned instead.

Notes

Given a vector V of length N, the median of V is the middle value of a sorted copy of V, V_sorted - i e., V_sorted[(N-1)/2], when N is odd, and the average of the two middle values of V_sorted when N is even.

Examples

>>> a = np.array([[10, 7, 4], [3, 2, 1]])
>>> a
array([[10,  7,  4],
       [ 3,  2,  1]])
>>> np.median(a)
3.5
>>> np.median(a, axis=0)
array([6.5, 4.5, 2.5])
>>> np.median(a, axis=1)
array([7.,  2.])
>>> m = np.median(a, axis=0)
>>> out = np.zeros_like(m)
>>> np.median(a, axis=0, out=m)
array([6.5,  4.5,  2.5])
>>> m
array([6.5,  4.5,  2.5])
>>> b = a.copy()
>>> np.median(b, axis=1, overwrite_input=True)
array([7.,  2.])
>>> assert not np.all(a==b)
>>> b = a.copy()
>>> np.median(b, axis=None, overwrite_input=True)
3.5
>>> assert not np.all(a==b)

How do you find the median in NumPy?

Results : Median of the array (a scalar value if axis is none) or array with median values along specified axis..
Given data points..
Arrange them in ascending order..
Median = middle term if total no. of terms are odd..
Median = Average of the terms in the middle (if total no. of terms are even).

Is there median function in NumPy?

NumPy median computes the median of the values in a NumPy array. The NumPy median function computes the median of the values in a NumPy array. Note that the NumPy median function will also operate on “array-like objects” like Python lists. Let's take a look at a simple visual illustration of the function.

How do you find the median of a list in Python?

You can write your own function in Python to compute the median of a list..
def get_median(ls):.
# sort the list..
ls_sorted = ls. sort().
# find the median..
if len(ls) % 2 != 0:.
# total number of values are odd..
# subtract 1 since indexing starts at 0..
m = int((len(ls)+1)/2 - 1).

How do you find the median of a list?

To find the median, first order the numbers from smallest to largest. Then find the middle number. For example, the middle for this set of numbers is 5, because 5 is right in the middle: 1, 2, 3, 5, 6, 7, 9..
{(7 + 1) ÷ 2}th..
= {(8) ÷ 2}th..
= {4}th..