How do you check if a string contains a certain word in python?
I'm working with Python, and I'm trying to find out if you can tell if a word is in a string. Show I have found some information about identifying if the word is in the string - using
mkrieger1 15.7k4 gold badges45 silver badges57 bronze badges asked Mar 16, 2011 at 1:10
1 What is wrong with:
Martin Thoma 112k148 gold badges568 silver badges873 bronze badges answered Mar 16, 2011 at 1:13
fabrizioMfabrizioM 44.8k15 gold badges97 silver badges115 bronze badges 13
but keep in mind that this matches a sequence of characters, not necessarily a whole word - for example,
answered Mar 16, 2011 at 1:52
Hugh BothwellHugh Bothwell 53.6k7 gold badges81 silver badges98 bronze badges 6 If you want to find out whether a whole word is in a space-separated list of words, simply use:
This elegant method is also the fastest. Compared to Hugh Bothwell's and daSong's approaches:
Edit: A slight variant on this idea for Python 3.6+, equally fast:
answered Apr 11, 2016 at 20:32
user200783user200783 13.2k11 gold badges63 silver badges124 bronze badges 6 You can split string to the words and check the result list.
Martin Thoma 112k148 gold badges568 silver badges873 bronze badges answered Dec 1, 2016 at 18:26
CorvaxCorvax 7447 silver badges11 bronze badges 3 find returns an integer representing the index of where the search item was found. If it isn't found, it returns -1.
Martin Thoma 112k148 gold badges568 silver badges873 bronze badges answered Mar 16, 2011 at 1:13
Matt HowellMatt Howell 15.4k7 gold badges47 silver badges56 bronze badges 0 This small function compares all search words in given text. If all search words are found in text, returns length of search, or Also supports unicode string search.
usage:
answered Jun 22, 2012 at 22:51
Guray CelikGuray Celik 1,2751 gold badge14 silver badges13 bronze badges 0 If matching a sequence of characters is not sufficient and you need to match whole words, here is a simple function that gets the job done. It basically appends spaces where necessary and searches for that in the string:
This assumes that commas and other punctuations have already been stripped out.
IanS 15.1k9 gold badges57 silver badges81 bronze badges answered Jun 15, 2012 at 7:23
daSongdaSong 4071 gold badge5 silver badges9 bronze badges 1 Using regex is a solution, but it is too complicated for that case. You can simply split text into list of words. Use split(separator, num) method for that. It returns a list of all the words in the string, using separator as the separator. If separator is unspecified it splits on all whitespace (optionally you can limit the number of splits to num).
This will not work for string with commas etc. For example:
If you also want to split on all commas etc. use separator argument like this:
Martin Thoma 112k148 gold badges568 silver badges873 bronze badges answered Dec 18, 2017 at 11:44
tstempkotstempko 1,1761 gold badge14 silver badges16 bronze badges 2 As you are asking for a word and not for a string, I would like to present a solution which is not sensitive to prefixes / suffixes and ignores case:
If your words might contain regex special chars (such as answered Aug 9, 2017 at 10:11
Martin ThomaMartin Thoma 112k148 gold badges568 silver badges873 bronze badges Advanced way to check the exact word, that we need to find in a long string:
Martin Thoma 112k148 gold badges568 silver badges873 bronze badges answered Nov 2, 2016 at 8:39
RameezRameez 5345 silver badges11 bronze badges What about to split the string and strip words punctuation?
If need, do attention to lower/upper case:
Maybe that way:
Sample:
I didn't check performance... answered Dec 26, 2020 at 5:18
marciomarcio 4165 silver badges16 bronze badges You could just add a space before and after "word".
This way it looks for the space before and after "word".
Martin Thoma 112k148 gold badges568 silver badges873 bronze badges answered Feb 26, 2015 at 14:23
PyGuyPyGuy 433 bronze badges 1 I believe this answer is closer to what was initially asked: Find substring in string but only if whole words? It is using a simple regex:
Martin Thoma 112k148 gold badges568 silver badges873 bronze badges answered Aug 25, 2021 at 13:25
Milos CuculovicMilos Cuculovic 18.9k50 gold badges154 silver badges264 bronze badges One of the solutions is to put a space at the beginning and end of the test word. This fails if the word is at the beginning or end of a sentence or is next to any punctuation. My solution is to write a function that replaces any punctuation in the test string with spaces, and add a space to the beginning and end or the test string and test word, then return the number of occurrences. This is a simple solution that removes the need for any complex regex expression.
To count the number of occurrences of a word in a string:
returns 1
returns 1 Use the function in an 'if' to test if the word exists in a string answered Mar 18 at 9:37
iStuartiStuart 3262 silver badges6 bronze badges How do I check if a string contains text?You can use contains(), indexOf() and lastIndexOf() method to check if one String contains another String in Java or not. If a String contains another String then it's known as a substring. The indexOf() method accepts a String and returns the starting position of the string if it exists, otherwise, it will return -1.
How do I check if a string contains a value in Python?Method #1 : Using isinstance(x, str)
This method can be used to test whether any variable is a particular datatype. By giving the second argument as “str”, we can check if the variable we pass is a string or not.
How do you check if a word is in a string pandas?str. contains() function is used to test if pattern or regex is contained within a string of a Series or Index. The function returns boolean Series or Index based on whether a given pattern or regex is contained within a string of a Series or Index.
How do you check a keyword in a string?How to check if a string is a keyword? Python in its language defines an inbuilt module “keyword” which handles certain operations related to keywords. A function “iskeyword()” checks if a string is a keyword or not. Returns true if a string is a keyword, else returns false.
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