How do you write a python program that accepts an integer n and computes the value of n nn nnn?

Python Basic: Exercise-10 with Solution

Write a Python program that accepts an integer (n) and computes the value of n+nn+nnn.

Sample value of n is 5

Python int(x, base=10):

The function returns an integer object constructed from a number or string x, or return 0 if no arguments are given. If x is a number, return x.__int__(). For floating point numbers, this truncates towards zero.

• If x is not a number or if base is given, then x must be a string, bytes, or bytearray instance representing an integer literal in radix base
• The literal can be preceded by + or - (with no space in between) and surrounded by whitespace
• A base-n literal consists of the digits 0 to n-1, with a to z (or A to Z) having values 10 to 35. The default base is 10.
• The allowed values are 0 and 2-36. Base-2, -8, and -16 literals can be optionally prefixed with 0b/0B, 0o/0O, or 0x/0X, as with integer literals in code.

Pictorial Presentation:

Sample Solution :-

Python Code:

a = int(input("Input an integer : "))
n1 = int( "%s" % a )
n2 = int( "%s%s" % (a,a) )
n3 = int( "%s%s%s" % (a,a,a) )
print (n1+n2+n3)

Sample Output:

615 

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This is a Python Program to read a number n and compute n+nn+nnn.

Problem Description

The program takes a number n and computes n+nn+nnn.

Problem Solution

1. Take the value of a element and store in a variable n.
2. Convert the integer into string and store it in another variable.
3. Add the string twice so the string gets concatenated and store it in another variable.
4. Then add the string thrice and assign the value to the third variable.
5. Convert the strings in the second and third variables into integers.
6. Add the values in all the integers.
7. Print the total value of the expression.
8. Exit.

Program/Source Code

Here is the source code of the Python Program to read a number n and compute n+nn+nnn. The program output is also shown below.

 
n=int(input("Enter a number n: "))
temp=str(n)
t1=temp+temp
t2=temp+temp+temp
comp=n+int(t1)+int(t2)
print("The value is:",comp)

Program Explanation

1. User must first enter the value and store it in a variable n.
2. The integer is converted to string for concatenation of the value of n.
3. The string is then concatenated once and twice and stored in separate variables.
4. Later to find the total sum, the string is converted back to integer.
5. The total value of the expression is then printed.

Runtime Test Cases

 
Case 1:
Enter a number n: 5
The value is: 615
 
Case 2:
Enter a number n: 20
The value is: 204060

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