How to find the middle character of a string in javascript

// the most amazing

const getMiddle = s => s.substr(s.length - 1 >>> 1, (~s.length & 1) + 1);

// should return "dd"

console.log(getMiddle('middle'))

// >>> is an unsigned right shift bitwise operator. It's equivalent to division by 2, with truncation, as long as the length of the string does not exceed the size of an integer in Javascript.

// About the ~ operator, let's rather start with the expression n & 1. This will tell you whether an integer n is odd (it's similar to a logical and, but comparing all of the bits of two numbers). The expression returns 1 if an integer is odd. It returns 0 if an integer is even.

// If n & 1 is even, the expression returns 0.

// If n & 1 is odd, the expression returns 1.

// ~n & 1 inverts those two results, providing 0 if the length of the string is odd, and 1 if the length of the sting is even. The ~ operator inverts all of the bits in an integer, so 0 would become -1, 1 would become -2, and so on (the leading bit is always the sign).

// Then you add one, and you get 0+1 (1) characters if the length of the string is odd, or 1+1 (2) characters if the length of the string is even.

@author by jacobb

the link of the source is: https://codepen.io/jacobwarduk/pen/yJpAmK

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Description

Javascript String Get word middle character

 P:Return the middle character of the word. 

If the word's length is odd, return the middle character.

If the word's length is even, return the middle 2 characters.

Examples:

getMiddle("test") should return "es"
getMiddle("testing") should return "t"
getMiddle("middle") should return "dd"
getMiddle("A") should return "A"

function getMiddle(s)
{
  const i = Math.floor(s.length / 2);
  let result = s[i];  
  if(s.length % 2 === 0 && i > 0) {
    result = s[i-1] + result;//from   w  w  w  . j  a  v  a  2s.com
  }
  return result;
}

const action = getMiddle("c");
console.log(action);

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