Does python enumerate start with 0?

In this tutorial, we will learn about the Python enumerate() method with the help of examples.

The enumerate() method adds a counter to an iterable and returns it (the enumerate object).

Example

languages = ['Python', 'Java', 'JavaScript']

enumerate_prime = enumerate(languages)

# convert enumerate object to list
print(list(enumerate_prime))

# Output: [(0, 'Python'), (1, 'Java'), (2, 'JavaScript')]

Syntax of enumerate()

The syntax of enumerate() is:

enumerate(iterable, start=0)

enumerate() Parameters

enumerate() method takes two parameters:

• iterable - a sequence, an iterator, or objects that supports iteration
• start (optional) - enumerate() starts counting from this number. If start is omitted, 0 is taken as start.

enumerate() Return Value

enumerate() method adds counter to an iterable and returns it. The returned object is an enumerate object.

You can convert enumerate objects to list and tuple using list() and tuple() method respectively.

Example 1: How enumerate() works in Python?

grocery = ['bread', 'milk', 'butter']
enumerateGrocery = enumerate(grocery)

print(type(enumerateGrocery))

# converting to list
print(list(enumerateGrocery))

# changing the default counter
enumerateGrocery = enumerate(grocery, 10)
print(list(enumerateGrocery))

Output

[(0, 'bread'), (1, 'milk'), (2, 'butter')]
[(10, 'bread'), (11, 'milk'), (12, 'butter')]

Example 2: Looping Over an Enumerate object

grocery = ['bread', 'milk', 'butter']

for item in enumerate(grocery):
  print(item)

print('\n')

for count, item in enumerate(grocery):
  print(count, item)

print('\n')
# changing default start value
for count, item in enumerate(grocery, 100):
  print(count, item)

Output

(0, 'bread')
(1, 'milk')
(2, 'butter')

0 bread
1 milk
2 butter

100 bread
101 milk
102 butter

In Python, you can get the element and index (count) from iterable objects such as list and tuple in for loop with the built-in function enumerate().

• Built-in Functions - enumerate() — Python 3.8.5 documentation

This article describes the following contents.

• How to use enumerate()
  • Normal for loop
  • for loop with enumerate()
• Start index at 1 with enumerate()
• Set step with enumerate()

See the following articles for more information about for loop and how to use enumerate() and zip() together.

• for loop in Python (with range, enumerate, zip, etc.)
• Use enumerate() and zip() together in Python

How to use enumerate()

Normal for loop

l = ['Alice', 'Bob', 'Charlie']

for name in l:
    print(name)
# Alice
# Bob
# Charlie

for loop with enumerate()

By passing an iterable object to enumerate(), you can get index, element.

for i, name in enumerate(l):
    print(i, name)
# 0 Alice
# 1 Bob
# 2 Charlie

Start index at 1 with enumerate()

As in the example above, by default, the index of enumerate() starts at 0.

If you want to start from another number, pass the number to the second argument of enumerate().

Start at 1:

for i, name in enumerate(l, 1):
    print(i, name)
# 1 Alice
# 2 Bob
# 3 Charlie

Start at the other number:

for i, name in enumerate(l, 42):
    print(i, name)
# 42 Alice
# 43 Bob
# 44 Charlie

For example, this is useful when generating sequential number strings starting from 1. It is smarter to pass the starting number to the second argument of enumerate() than to calculate i + 1.

for i, name in enumerate(l, 1):
    print('{:03}_{}'.format(i, name))
# 001_Alice
# 002_Bob
# 003_Charlie

Set step with enumerate()

There is no argument like step to specify increment to enumerate(), but it can be done as follows.

step = 3
for i, name in enumerate(l):
    print(i * step, name)
# 0 Alice
# 3 Bob
# 6 Charlie

Does enumerate in Python start at 0?

Does Python enumerate start at 1?

What does enumerate () do in Python?

What is the output of enumerate?