B5.write a python program to check whether an element exists within a tuple

Python tuple: Exercise-10 with Solution

Write a Python program to check whether an element exists within a tuple.

Sample Solution:-

Python Code:

tuplex = ("w", 3, "r", "e", "s", "o", "u", "r", "c", "e")
print("r" in tuplex)
print(5 in tuplex)

Sample Output:

True                                                                                                          
False 

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Sometimes, while working with data, we can have a problem in which we need to check if the data we are working with has a particular element. Let’s discuss certain ways in which this task can be performed. 

Method #1: Using loop 

This is a brute force method to perform this task. In this, we iterate through the tuple and check each element if it’s our, if found we return True. 

Python3

test_tup = (10, 4, 5, 6, 8)

print("The original tuple : " + str(test_tup))

N = 6

res = False

for ele in test_tup :

    if N == ele :

        res = True

        break

print("Does tuple contain required value ? : " + str(res))

Output : 

The original tuple : (10, 4, 5, 6, 8)
Does tuple contain required value ? : True

Method #2: Using in operator 

It is used to perform this task. It is a one-liner and recommended to perform this task. 

Python3

test_tup = (10, 4, 5, 6, 8)

print("The original tuple : " + str(test_tup))

N = 6

res = N in test_tup

print("Does tuple contain required value ? : " + str(res))

Output : 

The original tuple : (10, 4, 5, 6, 8)
Does tuple contain required value ? : True

Method: Using list comprehension method 

Python3

t = (10, 4, 5, 6, 8); n=6

x=[i for i in t if i==n]

print(["yes" if x else "no"])

Method: Using lambda function 

Python3

t = (10, 4, 5, 6, 8); n=6

x=tuple(filter(lambda i: (i==n),t))

print(["yes" if x else "no"])

Output

["yes"]

Method: Using the enumerate function

Python3

t = ('10', '4', '5', '6', '8'); n=6

x=[int(i) for i in t if int(i)==n]

print(["yes" if x else "no"])